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Bài 1 :
\(\frac{18}{23}:9=\frac{2}{23}\) \(8:\frac{3}{4}:\frac{4}{9}=\frac{32}{3}:\frac{4}{9}=24\)
Bài 2 :
0,25 x 6,9 x 4
= 0,25 x 4 x 6,9
= 1 x 6,9
= 6,9
7,2 x 4,7 + 72 : 0,1 + 7,2 x 4,3
= 7,2 x 4,7 + 7,2 x 10 + 7,2 x 4,3
= 7,2 x ( 4,7 + 10 + 4,3 )
= 7,2 x 19
= 136,8
14,7 x 31 + 29,4 + 67 x 14,7
= 14,7 x 31 + 14,7 x 2 + 67 x 14,7
= 14,7 x ( 31 + 2 + 67 )
= 14,7 x 100
= 1470
20,19 x 6 + 20,19 + 3 x 20,19
= 20,19 x ( 6 + 1 + 3 )
= 20,19 x 10
= 201,9
~ Thiên Mã ~
\(\frac{18}{23}.\frac{1}{9}=\frac{2}{23}.\frac{1}{1}=\frac{2}{23}\\ 8.\frac{4}{3}.\frac{9}{4}=8.\frac{1}{3}.\frac{9}{1}=\frac{8}{3}.9=\frac{72}{3}=4\\ mìnhchỉghicáchlàmkhôngghiđềbàinha\)
Lời giải:
$x:0,1+x:0,5-x:25\text{%}+x+x=2019$
$x\times 10+x\times 2-x\times 4+x+x=2019$
$x\times (10+2-4+1+1)=2019$
$x\times 10=2019$
$x=2019:10=201,9$
Đáp án A.
\(\frac{x+2019}{x+2018}=\frac{4038}{4037}\)
\(\Leftrightarrow4037(x+2019)=4038(x+2018)\)
\(\Leftrightarrow4037x+8150703=4038x+8148684\)
\(\Leftrightarrow4037x+8150703-4038x=8148684\)
\(\Leftrightarrow4037x-4038x+8150703=8148684\)
\(\Leftrightarrow-x=-2019\)
\(\Leftrightarrow x=2019\)
Ta có: \(\frac{x-2019}{2018}+\frac{x-2018}{2017}=\frac{x-2017}{2016}+\frac{x-2016}{2015}\)
\(\Leftrightarrow\left(\frac{x-2019}{2018}+1\right)+\left(\frac{x-2018}{2017}+1\right)=\left(\frac{x-2017}{2016}+1\right)+\left(\frac{x-2016}{2015}+1\right)\)
\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}=\frac{x-1}{2016}+\frac{x-1}{2015}\)
\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}-\frac{x-1}{2016}-\frac{x-1}{2015}=0\)
\(\Leftrightarrow\left(x-1\right)\left(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\right)=0\)
\(\Leftrightarrow x-1=0\)( vì \(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\ne0\))
\(\Leftrightarrow x=1\)
Vạy x=1
#)Giải :
( 20,19 x 100 - 20,19 x 100 ) = 2019
2019 - 2019 = 2019
0 = 2019
#)P/s : Bài toán tính kiểu j vậy bạn ? sao 0 = 2019 ? lỗi đề òi :v
#~Will~be~Pens~#
ko ghi lại đề
ta thấy : 2019 - 1 = 2018
2020 - 2 = 2018
2021 - 3 = 2018
2022 - 4 = 2018
=> x = 2018
thử lại :
2018+1/2019 + 2018+2/2020 = 2018+3/2021 + 2018+4/2022
= 1 + 1 = 1 + 1
2 = 2
Ta có : \(\frac{1}{n}+\frac{2020}{2019}=\frac{2019}{2018}+\frac{1}{n+1}\)
=> \(\frac{1}{n}-\frac{1}{n+1}=\frac{2019}{2018}-\frac{2020}{2019}\)
=> \(\frac{n+1}{n\left(n+1\right)}-\frac{n}{\left(n+1\right)n}=\frac{1}{4074342}\)
=> \(\frac{1}{n\left(n+1\right)}=\frac{1}{2018.2019}\)
=> n(n + 1) = 2018.2019
=> n(n + 1) = 2018.(2018 + 1)
=> n = 2018
