Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a,\(\frac{x}{-15}=\frac{-60}{x}\)=\(x^2\)= [-15 ] . [60] = 900 \(\Rightarrow\)x = + 30
a.
\(\frac{x}{-15}=\frac{-60}{x}=x^2=\left(-15\right):\left(60\right)=900\Rightarrow x=+30\)
a.
\(\frac{x}{-15}=-\frac{60}{x}\)
\(x\times x=15\times60\)
\(x^2=900\)
\(x^2=\left(\pm30\right)^2\)
\(x=\pm30\)
Vậy \(x=-30\) hoặc \(x=30\)
b.
\(-\frac{2}{x}=\frac{-x}{\frac{8}{25}}\)
\(x\times x=2\times\frac{8}{25}\)
\(x^2=\frac{16}{25}\)
\(x^2=\left(\pm\frac{4}{5}\right)^2\)
\(x=\pm\frac{4}{5}\)
Vậy \(x=\frac{4}{5}\) hoặc \(x=-\frac{4}{5}\)
Chúc bạn học tốt ^^
a/Theo bài ra ta có x.x= (-15).(-60)= \(x^2\)=900 mà 900= \(30^2\)suy ra x=30
.a, \(\frac{x+1}{999}+\frac{x+2}{998}=\frac{x+3}{997}+\frac{x+4}{996}\)
.\(< =>\frac{x+1}{999}+1+\frac{x+2}{998}+1=\frac{x+3}{997}+1+\frac{x+4}{996}+1\)
.\(< =>\frac{x+1}{999}+\frac{999}{999}+\frac{x+2}{998}+\frac{998}{998}=\frac{x+3}{997}+\frac{997}{997}+\frac{x+4}{996}+\frac{996}{996}\)
.\(< =>\frac{x+1+999}{999}+\frac{x+2+998}{998}=\frac{x+3+997}{997}+\frac{x+4+996}{996}\)
.\(< =>\frac{x+1000}{999}+\frac{x+1000}{998}-\frac{x+1000}{997}-\frac{x+1000}{996}=0\)
.\(< =>\left(x+1000\right)\left(\frac{1}{999}+\frac{1}{998}-\frac{1}{997}-\frac{1}{996}\right)=0\)
.Do \(\frac{1}{999}+\frac{1}{998}-\frac{1}{997}-\frac{1}{996}\ne0\)
.Suy ra \(x+1000=0\Leftrightarrow x=-1000\)
.b, \(\frac{x+1}{1001}+\frac{x+2}{1002}=\frac{x+3}{1003}+\frac{x+4}{1004}\)
.\(< =>\frac{x+1}{1001}-1+\frac{x+2}{1002}-1=\frac{x+3}{1003}-1+\frac{x+4}{1004}-1\)
.\(< =>\frac{x+1}{1001}-\frac{1001}{1001}+\frac{x+2}{1002}-\frac{1002}{1002}=\frac{x+3}{1003}-\frac{1003}{1003}+\frac{x+4}{1004}-\frac{1004}{1004}\)
.\(< =>\frac{x+1-1001}{1001}+\frac{x+2-1002}{1002}=\frac{x+3-1003}{1003}+\frac{x+4-1004}{1004}\)
.\(< =>\frac{x-1000}{1001}+\frac{x+1000}{1002}-\frac{x+1000}{1003}-\frac{x+1000}{1004}=0\)
.\(< =>\left(x-1000\right)\left(\frac{1}{1001}+\frac{1}{1002}-\frac{1}{1003}-\frac{1}{1004}\right)=0\)
.Do \(\frac{1}{1001}+\frac{1}{1002}-\frac{1}{1003}-\frac{1}{1004}\ne0\)
.Suy ra \(x-1000=0\Leftrightarrow x=1000\)
a) \(x^2=\left(-15\right).\left(-60\right)=900=>x=\)\(\pm\)\(30\)
b) \(-x^2=\dfrac{-16}{25}=>x^2=\dfrac{16}{25}=>x=\)\(\pm\)\(\dfrac{4}{5}\)
a)\(\dfrac{x}{-15}\)= \(-\dfrac{60}{x}\)
=> x . x = -15 . (-60)
=> \(^{x^2}\) = 900
x = 30
b) \(-\dfrac{2}{x}\) = \(-\dfrac{x}{\dfrac{8}{25}}\)
=> -2 . \(\dfrac{8}{25}\) = x . (-x)
=> \(\dfrac{-16}{25}\) = \(^{x^2}\)
=> x = \(\dfrac{4}{5}\)và \(-\dfrac{4}{5}\)
nhớ tích cho mk vs nha >_<
a)\(-x^2\left(x^2-4\right)=-25\left(x^2-4\right)\)
\(\Leftrightarrow-x^2=-25\)
\(\Leftrightarrow x^2=25\)
\(\Leftrightarrow x=\pm5\)
1.(2515.415)/(517.2016)=(530.230)/(517.516.232)=1/(53.22)=1/500
2.a,-x/2=8/-x=>-x.(-x)=2*8 =>x^2=16=(-4)^2=4^2
=>x=4 hoặc x=-4
b,(3/4)2x/(2/5)10=(15/8)10
(3/4)2x=(2/5*15/8)10
(3/4)2x=(3/4)10
2x=10
x=5
1) \(\frac{25^{15}\cdot4^{15}}{5^{17}\cdot20^{16}}\)
\(=\frac{5^{30}\cdot2^{30}}{5^{33}\cdot2^{32}}\)
\(=\frac{1}{5^3\cdot2^2}\)
\(=\frac{1}{500}\)
2)
a) \(\frac{-x}{2}=\frac{8}{-x}\)
\(\Rightarrow\left(-x\right)\left(-x\right)=8\cdot2\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x=\left\{\pm4\right\}\)
