Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 0)x( 9 - 8 + 7 - 6 + 5 - 4 - 3 + 2 - 1)x( 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 ×9)x()= 0 (vì 1-1+2-2+3+4-7 =0 )
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 52-|x-3|=80
<=> |x-3|=28
<=> x-3=28 hoặc x-3=-28
<=> x=31 hoặc x=-25
Đáp số x= 31 hoặc x=-25
2) x*(x+2)=0
<=> x=0 hoặc x+2=0
<=> x=0 hoặc x=-2
vậy .......
![](https://rs.olm.vn/images/avt/0.png?1311)
<=> 2x^2 +x-4x-2-5x-15=2x^2-6x+4+8x-2-2x
2x^2-8x-17-2x^2-2=0
-8x-19=0
x=-19/8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^{x+1}=9^x\)
\(\Leftrightarrow3^{x+1}=3^{2x}\)
\(\Leftrightarrow x+1=2x\)
\(\Leftrightarrow x+1=x+x\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
\(2^{3x+2}=4^{x+5}\)
\(\Leftrightarrow2^{3x+2}=2^{2x+10}\)
\(\Leftrightarrow3x+2=2x+10\)
\(\Leftrightarrow3x=2x+8\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)
\(2^{x+2}-2^x=96\)
\(\Leftrightarrow2^x.2^2-2^x.1=96\)
\(\Leftrightarrow2^x\left(2^2-1\right)=96\)
\(\Leftrightarrow2^x.3=96\)
\(\Leftrightarrow2^x=\frac{96}{3}\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2) \(\left(x-5\right)\left(x^2+1\right)=0\)
\(\Rightarrow x-5=0\) vì \(x^2+1>0\)
\(\Rightarrow x=5\)
cAU 1 TƯƠNG TỰ NHÉ
Tương tự sao được
a/ \(30.\left\{x+2+6\left(x-5\right)\right\}-24x=102\)
\(\Leftrightarrow30.\left\{x+2+6x-30\right\}-24x=102\)
\(\Leftrightarrow30.\left\{7x-28\right\}-24x=102\)
\(\Leftrightarrow210x-340-24x=102\)
\(\Leftrightarrow186x-340=102\)
\(\Leftrightarrow186x=442\)
\(\Leftrightarrow x=\frac{442}{186}\)
c/ \(\left(x+1\right)+\left(x+2\right)+....+\left(x+99\right)=0\)
\(\Leftrightarrow\left(x+x+...+x\right)+\left(1+2+......+99\right)=0\)
\(\Leftrightarrow99x+49500=0\)
\(\Leftrightarrow x=-50\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1. => 3x+6 = -6 hoặc 3x+6 = 6
=> x = -4 hoặc x=0
2. => (4-2x)^2 = 7+9 = 16
=> 4-2x=-4 hoặc 4-2x = 4
=> x=4 hoặc x=0
3. => 3x-5 = -4
=> x = 1/3
Tk mk nha
1) \(\left(3x+6\right)^2=36\)
\(\left(3x+6\right)^2=\orbr{\begin{cases}\left(-6\right)^2\\6^2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x+6=-6\\3x+6=6\end{cases}}\Rightarrow\orbr{\begin{cases}3x=-12\\3x=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-4\\x=0\end{cases}}\)
những câu sau tương tự
![](https://rs.olm.vn/images/avt/0.png?1311)
2x : 32 = 128
=> 2x = 128.32
=> 2x = 4096
=> 2x = 212
=> x = 12
X=12 X=5 X k thỏa mãn X=5 X=7 X k thỏa mãn X=1 lần lượt theo thứ tự nha
![](https://rs.olm.vn/images/avt/0.png?1311)
2/1/3:x+1/6.x
7/6:x+1/6.x=2/7
(7.1/6):x+1/6.x=2/7
1/6.7/x+1/6.x
1/6.(7/x+x)=2/7
7/x+x=12/7 bạn tự làm phần còn lại nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
1: Ta có: \(20-2\left(x+4\right)=4\)
\(\Leftrightarrow2\left(x+4\right)=16\)
\(\Leftrightarrow x+4=8\)
hay x=4
5: Ta có: \(\left(x+1\right)^3=27\)
\(\Leftrightarrow x+1=3\)
hay x=2
a) \(\frac{x+3}{2x-1}=\frac{2}{5}\) \(\left(x\ne\frac{1}{2}\right)\)
\(\Rightarrow\)\(5\left(x+3\right)=2\left(2x-1\right)\)
\(\Leftrightarrow\)\(5x+15=4x-2\)
\(\Leftrightarrow\)\(5x-4x=-2-15\)
\(\Leftrightarrow\)\(x=-17\)
Vậy...