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\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-x+6=102\)
\(125-x=102\)
\(x=125-102\)
\(x=23\)
a)
=>9x+1=937=>9x=936=>x=104
b)
=>199-(x-6)=24.2448=>-(x-6)=58752-199=>-x+6=58553=>-x=58547=>x=-58547
`2448:[119-(x-6)]=24`
`=>119-(x-6)= 2448 : 24`
`=>119-(x-6)= 102`
`=> x-6=119-102`
`=> x-6=17`
`=>x=17+6`
`=>x=23`
`2448:[119-(x-6)]=24`
`=>119-(x-6)= 2448 : 24`
`=>119-(x-6)= 102`
`=> x-6=119-102`
`=> x-6=17`
`=>x=17+6`
`=>x=23`
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
a) (x+12)-20=0
x+12=20
x=8
b) 5.(x-7)=0
x-7=0
x=7
c) 12x-3x+1=937
12x-3x=936
9x=936
x=104
d) 2448 : [ 119 - ( x - 6 ) ] = 24
119-(x-6) = 102
x-6=17
x=23
a ) ( x + 12 ) - 20 = 0
x + 12 = 0 + 20
x +12 = 20
x = 20 - 12
x = 8
b ) 5 . ( x - 7 ) =0
x - 7 = 0 : 5
x - 7 = 0
x = 0 + 7
x = 7
\(2448:\left[119.\left(x-6\right)\right]=24\)
\(119.\left(x-6\right)=2448:24=102\)
\(x-6=102:119\)
=> sai de
a) 8,2x + 1,8x = 0,3
x(8,2 + 1,8) = 0,3
10x = 0,3
x = 0,3 : 10
x = 0,03
b) 2448 : [119 - (x - 6)] = 24
119 - (x - 6) = 2448 : 24
119 - (x - 6) = 102
x - 6 = 119 - 102
x - 6 = 17
x = 17 + 6
x = 23
a, 8,2.x+1,8.x = 0,3
x.(8,2+1,8) = 0,3
x.10 = 0,3
x = 0,3:10
x = 3/100
b, 2448 : [119-(x-6)] = 24
119-(x-6) = 2448:24
119-(x-6) = 102
x-6 = 119-102
x-6 = 17
x = 17+6
x =23