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CÓ:
2x+4+2x+2=640
\(\Rightarrow2^x.2^4+2^x.2^2=640\)
\(\Rightarrow2^x.\left(2^4+2^2\right)=640\)
\(\Rightarrow2^x.20=640\)
\(\Rightarrow2^x=640:20\)
\(\Rightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
a) \(\left(0,75-40\%x\right).\frac{3}{4}-\frac{1}{4}=-2\frac{1}{3}\)
\(\Rightarrow\left(\frac{3}{4}-\frac{2}{5}x\right).\frac{3}{4}-\frac{1}{4}=-\frac{7}{6}\)
\(\Rightarrow\left(\frac{3}{4}-\frac{2}{5}x\right).\frac{3}{4}=-\frac{7}{3}+\frac{1}{4}\)
\(\Rightarrow\left(\frac{3}{4}-\frac{2}{5}x\right).\frac{3}{4}=-\frac{28}{12}+\frac{3}{12}=\frac{25}{12}\)
\(\Rightarrow\frac{3}{4}-\frac{2}{5}x=\frac{25}{12}:\frac{3}{4}=\frac{25}{12}.\frac{4}{3}=\frac{25}{9}\)
\(\Rightarrow\frac{2}{5}x=\frac{3}{4}-\frac{25}{9}=\frac{27}{36}-\frac{100}{36}=-\frac{73}{36}\)
\(\Rightarrow x=-\frac{73}{36}:\frac{2}{5}=-\frac{73}{36}.\frac{5}{2}=-\frac{365}{72}\)
\(2^{x+4}+2^{x+3}+2^{x+2}+2^{x+1}=1920\)
\(15.2^{x+1}=1920\)
\(2^{x+1}=1920:15\)
\(2^{x+1}=128\)
\(2^{x+1}=2^7\)
\(x+1=7\)
\(x=7-1\)
\(x=6\)
=> x = 6
3x+2=369
=>x+2=69
x=69-2
x=67
2x-5=810
2x-5=230
=>x-5=30
x=30+5
x=35
3x+2+3x=810
3x.32+3x=810
3x.(32+1)=810
3x.10=810
3x=810:10
3x=81
3x=34
=>x=4
5x+1-5x=500
5x.5-5x=500
5x.(5-1)=500
5x.4=500
5x=500:4
5x=125
5x=53
=>x=3
a) 3x+2 = 369
x + 2 = 69
x = 69 - 2
x = 67
b) 2x-5 = 810
2x-5 = 230
x - 5 = 30
x = 30 + 5
x = 35
c) 3x+2 + 3x = 810
3x . 9 + 3x . 1 = 810
3x . ( 9 + 1 ) = 810
3x . 10 = 810
3x = 810 : 10
3x = 81
3x = 34
=> x = 4
d) 5x+1 - 5x = 500
5x . 5 - 5x . 1 = 500
5x . ( 5 - 1 ) = 500
5x . 4 = 500
5x = 500 : 4
5x = 125
5x = 53
=> x = 3
a) \(3^{x+1}=729\)\(\Leftrightarrow3.3^x=729\Rightarrow3^x=243\Rightarrow3^x=3^5\Rightarrow x=5\)
b) \(2^x+2^{x+1}+2^{x+3}=704\Rightarrow2^x+2^x.2+2^x.2^3=704\Rightarrow2^x\left(1+2+8\right)=704\)
\(\Rightarrow2^x.11=704\Rightarrow2^x=64\Rightarrow2^x=2^5\Rightarrow x=5\)
\(x+1⋮x-1\)
\(x-1+2⋮x-1\)
\(2⋮x-1\)hay \(x-1\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
x - 1 | 1 | -1 | 2 | -2 |
x | 2 | 0 | 3 | -1 |
\(x-2⋮x+1\)
\(x+1-3⋮x+1\)
\(-3⋮x+1\)thự hiện tương tự nhé !
a) \(\frac{9}{20}\) c) \(\frac{-55}{4}\)
b) \(\frac{116}{75}\) d) \(\frac{-76}{45}\)
đúng hết đấy nhé mình tính kĩ lắm ko sai đâu
chúc may mắn
\(2^{x+1}=640-2^{x+3}\)
=>\(2^{x+1}+2^{x+3}=640\)
=>\(2^x\cdot2+2^x\cdot8=640\)
=>\(10\cdot2^x=640\)
=>\(2^x=64=2^6\)
=>x=6