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`3xx(x-1/6)-2xx(x-1/3)=2/3`
`3x-1/2-2x+2/3=2/3`
`x=2/3-2/3+1/2`
`x=1/2`
`3x(x-1/6)-2x(x-1/3)=2/3`
`3x^2 - 1/2 x- 2x^2 + 2/3x = 2/3`
`x^2+1/6 x =2/3`
`x=(-1 \pm \sqrt97)/12`
\(\left(x+9\right)+\left(x-8\right)+\left(x+7\right)+\left(x-6\right)+\left(x+5\right)+\left(x-4\right)+\left(x+3\right)+\left(x-2\right)+\left(x+1\right)=95.9\\ =>x+9+x-8+x+7+x-6+x+5+x-4+x+3+x-2+x+1=855\\ =>\left(x+x+x+x+x+x+x+x+x\right)+\left(9-8+7-6+5-4+3-2+1\right)=855\\ =>9x+5=855\\ =>9x=855-5\\ =>9x=850\\ =>x=\dfrac{850}{9}\)
\(\left(x+9\right)+\left(x-8\right)+...+\left(x-2\right)+\left(x+1\right)\)
\(=x+9+x-8+...+x-2+x+1\)
\(=\left(x+9+x-8\right)+...+\left(x+5\right)+...+\left(x-2+x+1\right)\)
(Ta gộp 4 số vào 1 tổng, riêng (x+5) là ta giữ nguyên)
\(=\left(2x-1\right)+...+\left(x+5\right)+...+\left(2x-1\right)\)
\(=4\left(2x-1\right)+\left(x+5\right)\)
\(=8x-4+x-5\)
\(=9x-9\) (1)
Từ bài toán trên, ta có:
\(\left(x+9\right)+\left(x-8\right)+...+\left(x-2\right)+\left(x+1\right)=95,9\)
Từ (1)
\(\Leftrightarrow9x-9=95,9\)
\(9x=95,9-9\)
\(x=86,9:9\)
\(x=9,6\left(5\right)\)
Barbie
x * ( x + 1 ) = 2 + 4 + 6 + ... + 2500
Số số hạng:
( 2500 - 2 ) : 2 + 1 = 1250 ( số hạng)
=> 2 + 4 + 6 + 8 + 10 + 2500
= ( 2500+ 2 ) * 1250 : 2
= 1563750
Ta có: x * ( x + 1 ) = 1563750
Màk 1563750 = 1250 * 1251
=> x = 1250
Ps : Mk ko chắc lắm!
^^ Chúc bạn học tốt nha!!!
a)\(\frac{24}{x}\times\frac{1}{4}=\frac{2}{5}\)
\(\frac{24}{x}=\frac{2}{5}:\frac{1}{4}\)
\(\frac{24}{x}=\frac{8}{5}\)
\(x=24:\frac{8}{5}\)
\(x=15\)
a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0+3/4.x = 9/10
3/4.x = 9/10
x = 9/10: 3/4
x = 6/5
b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5
x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5
x + 3/2. ( 1-1/15) = 11/5
x + 3/2.14/15 = 11/5
x + 7/5 = 11/5
x = 11/5 - 7/5
x = 4/5
\(\left(x+2\right)+\left(x+4\right)+...+\left(x+20\right)=160\)
\(x+2+x+4+...+x+20=160\)
\(\left(x+x+x+...+x\right)+\left(2+4+...+20\right)=160\)
\(x\cdot20+\frac{\left(20+2\right)\cdot\left(\left(20-2\right):2+1\right)}{2}=160\)
\(x\cdot20+110=160\)
\(x\cdot20=160-110\)
\(x\cdot20=50\)
\(x=50:20\)
\(x=2,5\)
Vậy \(x=2,5\)
[ x + 2 ] + [ x + 4 ] + [ x + 6 ] + ... + [ x + 20 ] = 160
( 20 + 2 ) x 10 : 2 + 10x = 160
22 x 10 : 2 + 10x = 160
220 : 2 + 10x = 160
110 + 10x = 160
10x = 160 - 110
10x = 50 ; x = 5
[ 1/2 + 1/4 + 1/8 + ... + 1.64 ] /x = 3/8
=> [ ( 1/2 + 1/4 ) + ( 1/8 + 1/16 ) + ( 1/32 + 1/64 ) ] / x = 3/8
[ 3/4 + 3/16 + 3/64 ] / x = 3/8
[ 48/64 + 12/64 + 3/64 ] / x = 3/8
=> 63/64x = 3/8
=> 64x = 21 x 8
64x = 168
x = 2,625
k chắc nha
1/3+1/6+X/4042 =1
=> 1/6 + X/4042 = 1 - 1/3 = 2/3
=> X/4042 = 2/3 - 1/6 = 1/2
=> X/4042 = 2021/4042
=> X = 2021
Vậy X = 2021
cảm ơn bạn nha