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Tìm x:
2480 - 4710 : 3 + [ 200 - ( 15x - 5 ) ] = 1010.
=> 2480-1570+[200-(15x-5)]=1010
=> 910+[200-(15x-5)]=1010
=> 200-(15x-5)=1010-910
=> 15x-5=200-100
=> 15x=100+5
=> x=105:15
=> x=7
2480 - 4710 : 3 + [ 200 - ( 15x - 5) ] = 1010
4710:3+[200-(15x-5)]=2480-1010
4710:3+[200-[15x-5]]=1470
1570+[200-[15x-5]]=1470
200-[15x-5]=1470-1570
200-[15x-5]=-100
15x-5=200+100
15x-5=300
15x=300-5
15x=295
x=295:15
2480 - 4710 : 3 + ( 200 - ( x - 5 ) ) = 1010
2480 - 1570 + (200 - ( x - 5 ) ) = 1010
910 + 200 - ( x - 5 ) = 1010
1010 - ( x - 5 ) = 1010
x - 5 = 0
x = 5
Vậy x = 5
2480 -4710 : 3 + [ 200 - ( x -5 ) ] = 1010
=> 2480-1570+[200-x+5]=1010
=> 910+200-x+5=1010
=> 1110-x+5=1010
=> 1115-x=1010
=> x=1115-1010
=> x=105
nhanh hộ mình với mình sắp đi học rồi.Ai trả lời đc mình cho 1 k nhanh nhanh lên nha, nguy cấp rồi đó
a,(72000+18000)-(3x+3000)=12000
90000-(3x+3000)=12000
3x+3000=90000-12000
3x+3000=78000
3x=78000-3000
3x=75000
x=75000:3
x=25000
b,[3.(x+2):7]:4=120
3.(x+2):7=120:4
3.(x+2):7=30
3.(x+2)=30.7
3.(x+2)=210
x+2=210:3
x+2=70
x=70-2
x=68
\(a,\left(3x+5\right)+105=200\)
\(3x+5=95\)
\(3x=90\)
\(x=90:3\)
\(x=30\)
\(b,\left(x-4\right).\left(3x-15\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\3x-15=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=5\end{cases}}\)
\(c,\left(72000+18000\right)-\left(3x+3000\right)=1200\)
\(90000-\left(3x+3000\right)=1200\)
\(3x+3000=88800\)
\(3x=85800\)
\(x=28600\)
\(d,\left[3.\left(2+x\right):7\right].4=120\)
\(3.\left(2+x\right):7=30\)
\(3.\left(2+x\right)=210\)
\(2+x=70\)
\(x=68\)
\(e,2480-4710:3+\left[200-\left(x-5\right)\right]=1010\)
\(2480-1570+\left(200-x+5\right)=1010\)
\(910+\left(205-x\right)=1010\)
\(205-x=100\)
\(x=105\)
a: =>2480-1570+(205-x)=1010
=>205-x=100
hay x=105
b: \(\Leftrightarrow x\cdot\dfrac{1}{2}\cdot\dfrac{13}{12}=\dfrac{7}{60}\cdot3\cdot4=\dfrac{7}{5}\)
=>x=168/65
a: \(\Leftrightarrow\left[\left(3x+14\right):4-3\right]:2=1\)
=>(3x+14):4-3=2
=>(3x+14):4=5
=>3x+14=20
=>3x=6
hay x=2
b: \(\Leftrightarrow\left[\left(x:4+17\right):10+3\cdot16\right]:10=5\)
\(\Leftrightarrow\left(x:4+17\right):10=50-48=2\)
=>x:4+17=20
=>x:4=3
hay x=12
c: \(\Leftrightarrow2\cdot15^2+\left[2\cdot125-\left(2x+4\right)\cdot5\right]:19=453\)
\(\Leftrightarrow250-\left(2x+4\right)\cdot5=\left(453-450\right)\cdot19=57\)
=>5(2x+4)=197
=>2x+4=197/5
=>2x=177/5
hay x=177/10
d: \(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)
=>19x+50=126
=>19x=76
hay x=4
e: \(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}=18\cdot3^{12}\)
\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)
hay x=14
f: \(\Leftrightarrow3\left(x+2\right):7=30\)
=>3(x+2)=210
=>x+2=70
hay x=68
g: \(2480-1570+200-x+5=1010\)
=>1115-x=1010
hay x=105