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\(a,ƯCLN\left(540,168\right)=12\\ \RightarrowƯC\left(540,168\right)=Ư\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\\ b,ƯCLN\left(735,350\right)=35\\ \RightarrowƯC\left(735,350\right)=Ư\left(35\right)=\left\{-35;-7;-5;-1;1;5;7;35\right\}\)
\(b,ƯCLN\left(70,540,1225\right)=35\\ \RightarrowƯC\left(70,540,1225\right)=Ư\left(35\right)=\left\{1;5;7;35\right\}\\ d,ƯCLN\left(48,24,60\right)=12\\ \RightarrowƯC\left(48,24,60\right)=Ư\left(12\right)=\left\{1;2;3;4;6;12\right\}\\ g,ƯCLN\left(3780,4320,5184\right)=108\\ \RightarrowƯC\left(3780,4320,5184\right)=Ư\left(108\right)=\left\{1;2;3;4;6;9;12;18;27;36;54;108\right\}\)
a)225=32.52
270=2.5.33
360=23.32.5
=> ƯCLN 225;270;360=32.5=45
=>ƯC225;270;360=ước 45=1;3;5;9;15;45
b)540=22.33.5
756=33.22.7
1512=33.23.7
=>ưcln 540;756;1512=22.33=108
=>ưc 540;756;1512=ư 108=1;2;3;4;6;9;12;18;24;27;36;48;54;72;108
a) Ta có : 225 = 32. 52
270 = 2 . 33 . 5
360 = 23. 32.5
→ ƯCLN= 32. 5 = 45
→ ƯC( 225,270,360)= Ư(45)
→ Ư(45) = \(\left\{1;3;5;9;15;45\right\}\)
Vậy ƯC( 225 ; 270; 360) =\(\left\{1;3;5;9;15;45\right\}\)
b) Ta có : 540 = 22. 33.5
756 = 22.33.7
1512 = 23. 33.7
→ ƯCLN( 540;756;1512)=22.33=108
→ƯC(540;756;1512)=Ư( 108)= \(\left\{1;2;3;4;6;9;12;18;27;36;54;108\right\}\)
Vậy ƯC( 540; 756;1512)= \(\left\{1;2;3;4;6;9;12;18;27;36;54;108\right\}\)
a, Ta có : 225 = \(3^2.5^2\)
270 = \(2.3^3.5\)
360 = \(2^3.3^2.5\)
ƯCLN\(_{\left(225,270,360\right)}\)= \(3^2.5=45\)
\(ƯC_{\left(225,270,360\right)}=Ư_{\left(45\right)}=\left\{1;3;5;9;15;45\right\}\)b, Ta có : 540 = \(2^2.3^3.5\)
756 = \(2^2.3^3.7\)
1512 = \(2^3.3^3.7\)
\(\RightarrowƯCLN_{\left(540,756,1512\right)}=2^2.3^3=108\)
\(ƯC_{\left(540,756,1512\right)}=Ư_{\left(108\right)}=\left\{1;2;3;4;6;9;12;18;108\right\}\)
a) Ta có:
90 = 2 × 32 × 5
126 = 2 × 32 × 7
=> ƯCLN(90; 126) = 2 × 32 = 18
=> ƯC(90; 126) = Ư(18) = {1 ; -1 ; 2 ; -2 ; 3 ; -3 ; 6 ; -6 ; 9 ; -9 ; 18 ; -18}
b) Do 480 chia hết cho a, 600 chia hết cho a
=> a thuộc ƯC(480; 600)
Mà a lớn nhất => a = ƯCLN(480; 600) = 120
Ta có : 648 = 23.34
540 = 22.33.5
=> ƯCLN(648; 540) = 22.33 = 108
=> ƯC(648; 540) = Ư(108) = {\(\pm1;\pm2;\pm3;\pm4;\pm6;\pm9;\pm12;\pm18;\pm27;\pm36;\pm54;\pm108\)}
@Hoàng Việt
Ta có: \(648=2^3.3^4\)
\(540=2^2.3^3.5\)
\(\Rightarrow\) \(ƯCLN\) (648;540) = \(2^2.3^3=4.27=108\)
\(\RightarrowƯC\left(648;540\right)\inƯ\left(108\right)\)
\(\RightarrowƯC\left(648;108\right)\in\left\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm9;\pm12;\pm18;\pm24;\pm36;\pm108\right\}\)Chúc bn hk tốt!
Ta có:
\(206=2\cdot103\\ 540=2^2\cdot3^3\cdot5\)
Vậy ƯCLN của 206 và 540 là 2.