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NV
8 tháng 10 2019

ĐKXĐ:

a/ \(\left\{{}\begin{matrix}3x+4\ge0\\x-3\ne0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x\ge-\frac{4}{3}\\x\ne3\end{matrix}\right.\)

b/ \(x^2-5x+6\ne0\Rightarrow\left(x-2\right)\left(x-3\right)\ne0\Rightarrow\left\{{}\begin{matrix}x\ne2\\x\ne3\end{matrix}\right.\)

c/ \(\left\{{}\begin{matrix}4-x^2\ge0\\\left(x-2\right)\left(x-3\right)\ne0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}-2\le x\le2\\x\ne2\\x\ne3\end{matrix}\right.\)

\(\Rightarrow-2\le x< 2\)

d/ \(\left\{{}\begin{matrix}4-x\ge0\\2x-10\ge0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x\le4\\x\ge5\end{matrix}\right.\) \(\Rightarrow x=\varnothing\)

NV
8 tháng 10 2019

a/ ĐKXĐ: \(\left\{{}\begin{matrix}2x+1\ge0\\3\left|x\right|^2+5\left|x\right|-2\ne0\\x-\left|x\right|\ne0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x\ge-\frac{1}{2}\\\left|x\right|\ne\frac{1}{3}\\x< 0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}-\frac{1}{2}\le x< 0\\x\ne-\frac{1}{3}\end{matrix}\right.\)

b/ Nếu \(x\in D\Rightarrow-x\in D\)

\(f\left(-x\right)=\frac{\left|-2017x-10\right|-\left|-2017x+10\right|}{x^6-8x^4+16x^2}\)

\(=\frac{\left|2017x+10\right|-\left|2017x-10\right|}{x^6-8x^4+16x^2}=-\frac{\left|2017x-10\right|-\left|2017x+10\right|}{x^6-8x^4+16x^2}=-f\left(x\right)\)

Hàm lẻ

NV
10 tháng 10 2019

ĐKXĐ:

a/ \(\left\{{}\begin{matrix}x\ge1\\4-x^2\ge0\\x\ne2\\x\ne-3\end{matrix}\right.\) \(\Rightarrow1\le x< 2\)

b/ \(\left\{{}\begin{matrix}2-x\ge0\\x^2-5x+4\ne0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x\le2\\x\ne1\\x\ne5\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x\le2\\x\ne1\end{matrix}\right.\)

c/ \(\left\{{}\begin{matrix}2-3x\ge0\\1+2x>0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x\le\frac{2}{3}\\x>-\frac{1}{2}\end{matrix}\right.\) \(\Rightarrow-\frac{1}{2}< x\le\frac{2}{3}\)