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Đáp án là B
Ta có:
- 12 2 .x = 56 + 10.13x
144x = 56 + 130x
144x - 130x = 56
14x = 56
x = 4
a) 2|x+1|=10
\(\left|x+1\right|\) = 10:2
\(\left|x+1\right|\) = 5
\(\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\) \(\Rightarrow\) \(\left[{}\begin{matrix}x=5-1\\x=\left(-5\right)-1\end{matrix}\right.\) \(\Rightarrow\) \(\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
b) (−12)2x=56+10.13x
144x= 56+130x
144x-130x= 56
14x= 56
x= 56: 14
x= 4
a) 2\(|\)x + 1\(|\) = 10 \(\Rightarrow\) \(|\)x + 1\(|\) = 5
\(\Rightarrow\) x + 1 = 5 hay x = 4
hoặc x + 1 = \(-\)5 hay x = \(-\)6.
ĐS : x = 4, x = \(-\)6.
b) x = 4.
= 144 . x = 56 + 130. x
= 144 . x - 130 . x = 56
= x.[144 - 130] = 56
= x.14 = 56
= x = 56 : 14
= x = 4
x + (-23 ) = -100 + 77
x + ( -23 ) = -23
x = -23 - ( -23 )
x = -23 + 23
x = 0
( -15 ) + x = ( -14 ) - ( -57 )
( -15 ) + x = 43
x = 43 - ( -15 )
x = 43 + 15
x = 58
Mấy câu còn lại cũng dễ bn tự làm nha! Bye bye
\(x+\left(-23\right)=-100+77\)
\(\Leftrightarrow x-23=-23\)
\(\Leftrightarrow x=-23+23\)
\(\Leftrightarrow x=0\)
\(-15+x=-14-\left(-57\right)\)
\(\Leftrightarrow-15+x=43\)
\(\Leftrightarrow x=43+15\)
\(\Leftrightarrow x=48\)
\(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Leftrightarrow11-26=x-16\)
\(\Leftrightarrow x-16=15\)
\(\Leftrightarrow x=-15+16\)
\(\Leftrightarrow x=1\)
\(x-\left(17-x\right)=x-7\)
\(\Leftrightarrow x-17+x=x-7\)
\(\Leftrightarrow2x+17=x-7\)
\(\Leftrightarrow x-2x=7-17\)
\(\Leftrightarrow-x=-10\)
\(\Leftrightarrow x=10\)
\(\left(-12\right)^{2x}=56+10.13x\)
\(\Leftrightarrow144^x=56+10.13x\)
\(2x\left(y-1\right)+y-1=11\Leftrightarrow\left(2x+1\right)\left(y-1\right)=11\)
\(\Rightarrow2x+1;y-1\inƯ\left(11\right)=\left\{\pm1;\pm11\right\}\)
2x+1 | 1 | -1 | 11 | -11 |
y-1 | 11 | -11 | 1 | -1 |
x | 0 | -1 | 5 | -6 |
y | 12 | -10 | 2 | 0 |
\(x+4⋮x+1\)
\(=>x+1+3⋮x+1\)
Vì x + 1 chia hết cho x + 1
x + 1 + 3 chia hết cho x + 2
=> 3 chia hết cho x + 1
=> x + 1 thuộc Ư ( 3 )
=> x + 1 thuộc { 1 ; 3 }
=> x thuộc { 0 ; 2 }
1. x + 2x = -36
=> 3x = -36
=> x = -36 : 3
=> x = -12
2. (2x + 3) \(⋮\)(x - 2)
=> (2x - 2) + 5 \(⋮\)(x - 2)
=> 2(x - 2) + 5 \(⋮\)(x - 2)
=> 5 \(⋮\)(x - 2)
=> x - 2 \(\in\)Ư(5) = {-5;-1;1;5}
=> x \(\in\){-3;1;3;7}
3. Khi đó a . (-b) = -132
4. -2(3x + 2) = 12 + 22 + 32
=> -2(3x + 2) = 1 + 4 + 9
=> -2(3x + 2) = 14
=> 3x + 2 = 14 : (-2)
=> 3x+ 2 = -7
=> 3x = -7 - 2
=> 3x = -9
=> x = -9 : 3
=> x = -3
1/ \(x+2x=-36\)
\(\Rightarrow3x=-36\)
\(\Rightarrow x=-\frac{36}{3}\)
\(\Rightarrow x=-12\)
2/ \(\left(2x+3\right)⋮\left(x-2\right)\)
\(\Leftrightarrow\left(2x-4\right)+7⋮\left(x-2\right)\)
\(\Leftrightarrow2\left(x-2\right)+7⋮\left(x-2\right)\)
\(\Rightarrow7⋮\left(x-2\right)\)
\(\Rightarrow\left(x-2\right)\inƯ\left(7\right)\)
\(\Rightarrow x\inƯ\left(7-2\right)\)
\(\Rightarrow x\inƯ\left(5\right)\)
\(\Rightarrow x\in\left\{-5,1,5\right\}\)
Vậy x nhỏ nhất để \(\left(2x-3\right)⋮\left(x-2\right)\) là -5
3/ Vì \(a\cdot b=32\)
\(\Rightarrow-a\cdot b=-\left(a\cdot b\right)=-32\)
4/ \(-2\left(3x+2\right)=1^2+2^2+3^2\)
\(\Leftrightarrow-6x-4=1+4+9\)
\(\Leftrightarrow-6x=14+4\)
\(\Leftrightarrow-6x=18\)
\(\Leftrightarrow x=\frac{18}{-6}\)
\(\Rightarrow x=3\)
\((-12)^2\cdot x=56-(-10)\cdot13x\)
\(\Rightarrow144\cdot x=56-(-130x)\)
\(\Rightarrow144x=56+130x\)
\(\Rightarrow144x-130x=56\)
\(\Rightarrow14x=56\)
\(\Rightarrow x=4\)
P/S : Hoq chắc :D