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a) x=\(\dfrac{5.6}{-10}=-3.\)
b) y=\(\dfrac{3.77}{-33}=-7.\)
4\(\dfrac{1}{3}.\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\)\(\le x\le\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
\(\dfrac{-13}{9}\le x\le\dfrac{-11}{12}\)
\(\dfrac{-468}{36}\le\dfrac{36.x}{36}\le\dfrac{-396}{36}\)
\(=>36.x\in\left\{-467;-466;-465;-464;...;-398;-397\right\}\)
\(=>x=-12\)
Tìm x biết:
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{4}\)
\(\Leftrightarrow\left(4,5-2x\right)=\dfrac{11}{4}:1\dfrac{4}{7}\)
\(\Leftrightarrow4,5-2x=\dfrac{7}{4}\)
\(\Leftrightarrow2x=4,5-\dfrac{7}{4}\)
\(\Leftrightarrow2x=\dfrac{11}{4}\)
Vậy \(x=\dfrac{11}{8}\)
Tìm số nguyên x biết:
Theo đề bài, ta có:
\(4\dfrac{1}{3}\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
\(\Leftrightarrow-\dfrac{13}{9}\le x\le-\dfrac{11}{18}\) hay \(-\dfrac{26}{18}\le x\le-\dfrac{11}{18}\)
\(\Leftrightarrow-1,\left(4\right)\le x\le-0,6\left(1\right)\)
Mà \(x\in Z\) nên x=-1
Vậy x = -1
a) x.21=6.7
x.21=42
x=42:21
x = 2
b) y . 20 = -5.28
y.20 = -140
y = (-140) : 20
y = -7
a)=>x*21=7*6
=>x*21=42
=>x=42/21
x=2
b)=>y*20=(-5)*28
=>y*20=-140
=>y=-140/20
y=-7
b) \(\left(\dfrac{1}{2}+2x\right).\dfrac{2}{3}=\dfrac{5}{6}\\ \dfrac{1}{2}+2x=\dfrac{5}{6}:\dfrac{2}{3}\\ \dfrac{1}{2}+2x=\dfrac{5}{6}.\dfrac{3}{2}\\ \dfrac{1}{2}+2x=\dfrac{5}{4}\\ 2x=\dfrac{5}{4}-\dfrac{1}{2}\\ 2x=\dfrac{5}{4}-\dfrac{2}{4}\\ 2x=\dfrac{3}{4}\\ x=\dfrac{3}{4}:2\\ x=\dfrac{1}{2}\)
Cho mình sửa lại nha:
\(\left(\dfrac{1}{2}+2x\right).\dfrac{2}{3}=\dfrac{5}{6}\\ \dfrac{1}{2}+2x=\dfrac{5}{6}:\dfrac{2}{3}\\ \dfrac{1}{2}+2x=\dfrac{5}{6}.\dfrac{3}{2}\\ \dfrac{1}{2}+2x=\dfrac{5}{4}\\ 2x=\dfrac{5}{4}-\dfrac{1}{2}\\ 2x=\dfrac{5}{4}-\dfrac{2}{4}\\ 2x=\dfrac{3}{4}\\ x=\dfrac{3}{4}:2\\ x=\dfrac{3}{8}\)
a) \(x\)=1 \(y\)= 12
b)\(x\)=4 \(y\)= 14
hoặc \(x\)= 6 \(y \)=21
...
=>2x=-18
hay x=-9