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a) \(\frac{4^2.4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2.3\right)^5}{\left(0,2\right)^6}=\frac{3^5.0,2^5}{0,2^6}=\frac{3^5}{0,2}=\frac{243}{0,2}=1215\)
c) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3}{2^{11}}=\frac{3}{2^4}=\frac{3}{16}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}=\frac{6^2\left(6+3\right)+3^3}{-13}=\frac{6^2.9+3^2}{-13}=\frac{3^2\left(6^2+1\right)}{-13}=\frac{9.37}{-13}=\frac{333}{-13}\)
a,\(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{4^5}{4^5}=1\)
\(\frac{\left(0.6\right)^5}{\left(0.2\right)^6}=1215\)
còn lại làm đc mà
\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,6\right)^5}{\left(0,2\right)^5.0,2}=\left(\frac{0,6}{0,2}\right)^5.\frac{1}{\frac{1}{5}}=3^5.5=243.5=1215\)
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3.3^5}{2^7.2^4.3^5}=\frac{3}{16}\)
b)\(\frac{0,6^5}{0,2^6}=\frac{0,2^5.0,3^5}{0,2^6}=\frac{0,3^5}{0,2}=0,01215\)
a/ \(\frac{4^2.4^3}{2^{10}}=\frac{16.64}{1064}=\frac{384}{1064}=\frac{3}{8}\) b/ \(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\frac{243}{3125}}{\frac{1}{15625}}=1215\)
c/ \(\frac{2^7.9^3}{6^5.8^2}=\frac{128.729}{7776.64}=\frac{93312}{497664}=\frac{3}{16}\) d/ \(\frac{6^3+3.6^2+3^3}{-13}=\frac{216+3.36+27}{-13}=\frac{216+108+27}{-13}=\frac{351}{-13}=-27\)
\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\right)^5\cdot3^5}{\left(0,2\right)^6}=\frac{3^5}{0.2}=243:\frac{1}{5}=1215\)
\(\frac{2^7\cdot9^3}{6^5\cdot8^2}=\frac{2^7\cdot\left(3^2\right)^3}{2^5\cdot3^5\cdot\left(2^3\right)^2}=\frac{2^7\cdot3^6}{2^{11}\cdot3^5}=\frac{3}{2^4}=\frac{3}{16}\)
câu cuối ko bt
Xin lỗi vì đã ns dối, ko phải tớ ko bt giải mà là tại mama kêu ghê quá nên ko kịp viết lời giải câu cuối
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\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{2^3\cdot3^3+3\cdot2^2\cdot3^2+3^3}{-13}=\frac{2^3\cdot3^3+3^3\cdot2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{27\cdot13}{-13}=-27\)