Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{72-28-14}{99}\)\(=\frac{30}{99}=\frac{10}{33}\)
\(\left(69,78+30,22\right)+35,97\)\(=100+35,97=135,97\)
\(83,45-\left(30,98+42,47\right)\)\(=83,45-73,45=10\)
72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99-42/99
=30/99=10/33
67,78+35,97+30,22
=(67,78+30,22)+35,97
=98+35,97
=133,97
83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
a) 7/11+3/4+4/11+1/4
=(7/11+4/11)+(3/4+1/4)
= 1 + 1
= 2.
b) 72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99- 42/99
= 30/99=10/33.
c) 69,78+35,97+30,22
=(69,78+30,22)+35,97
= 100 +35,97
= 135,97.
d) 83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45- 73,45
= 10.
7/11 + 3/4 + 4/11 +1/4
= ( 7/11 + 4/11 ) + ( 3/4 + 1/4 )
= 1 + 1
= 2
72/99 - 28/99 - 14/99
= 72/99 - ( 28/99 + 14/99 )
= 72/99 - 42/99
= 50/99
69,78 + 35,97 + 30,22
= ( 69,78 + 30,22 ) + 35,97
= 100 + 35,97
= 135,97
83,45 - 30,98 - 42,47
= 83,45 - ( 30,98 + 42,47 )
= 83,45 - 73,45
= 10
a) \(\dfrac{7}{11}+\dfrac{3}{4}+\dfrac{4}{11}+\dfrac{1}{4}=\left(\dfrac{7}{11}+\dfrac{4}{11}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=1+1=2\)
b) \(\dfrac{72}{99}-\dfrac{28}{99}-\dfrac{14}{99}=\dfrac{72-28-14}{99}=\dfrac{30}{99}=\dfrac{10}{33}\)
1 Tính
7/12 - 2/7 + 1/12= (7/12-1/12)+2/7=6/12+2/7=1/2+2/7=7/14+4/14=11/14
12/17-5/17-4/17= 12-5-4/17=3/17
2a, 7/11+3/4+4/11+1/4= (7/11+4/11)+3/4+1/4=11/11+4/4=1+1=2
b)72/99-28/99-14/99= (72-28-14)/99=30/99=10/33
c)69,78+35,97+30,22= (69,78+30,22)+35,97=100+35,97=135,97
d) 83,45-30,98-42,47=83,45-(30,98+42,47)=83,45-73,45=10
69,78 + 35,97 + 30,22 = (69,78 + 30,22) + 35,97=100 + 35,97=135,97
83,45 - 30,98 - 42,47 = 83,45 - (30,98 + 42,47) = 83,45 - 73,45 = 10
a)69,78 + 35,97 + 30,22
=(69,78+30,22)+35,97
=100 + 35,97
=135,97
b)83,45 - 30,98 - 42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
a) (69,78+30,22)+35,97
=100+35,97
=135,97