Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1)Ta có : 212121/353535 = 212121:10101/353535:10101 = 21/35 = 3/5
131313/141414 = 131313:10101/141414:10101 = 13/14
Ta có : 3/5 = 42/70 ; 13/14 = 65/70
Vì 42<65 => 42/70<65/70 => 212121/353535<131313/141414
2)Ta có : 2012/2013<1
2013/2014<1
2014/2015<1
=> 2012/2013+ 2013/2014+ 2015/2012<1+1+1=3
Vậy 2012/2013+ 2013/2014+ 2015/2012<3
\(N=\frac{2012+2013+2014}{2013+2014+2015}=\frac{2012}{2013+2014+2015}+\frac{2013}{2013+2014+2015}+\frac{2014}{2013+2014+2015}\)
Ta thấy: \(\frac{2012}{2013}>\frac{2012}{2013+2014+2015}\)
\(\frac{2013}{2014}>\frac{2013}{2013+2014+2015}\)
\(\frac{2014}{2015}>\frac{2014}{2013+2014+2015}\)
\(\Rightarrow M=\frac{2012}{2013}+\frac{2013}{2014}+\frac{2014}{2015}>N=\frac{2012}{2013+2014+2015}+\frac{2013}{2013+2014+2015}+\frac{2014}{2013+2014+2015}\)
Vậy M>N
Ta thấy B=2012+2013/2013+2014<1(vì 2012+2013<2013+2014)
Ta có A=2012/2013+2013/2014
A=1-1/2013+1-1/2014
A=(1+1)-(1/2013+1/2014)
A=2-(1/2013+1/2014)
Mà 1/2013<1/2;1/2014<1/2
=>1/2013+1/2014<1/2+1/2=1
=>2-(1/2013+1/2014)>1
=>A>1
Mà B<1
=>A>B
\(B=\frac{2012+2013}{2013+2014}=\frac{2012}{2013+2014}+\frac{2013}{2013+2014}< \frac{2012}{2013}+\frac{2013}{2014}=A\)
Vậy B<A
\(\frac{\frac{1}{2012}+\frac{1}{2013}-\frac{1}{2014}}{\frac{5}{2012}+\frac{5}{2013}-\frac{5}{2014}}-\frac{\frac{2}{2013}+\frac{2}{2014}-\frac{2}{2015}}{\frac{3}{2013}+\frac{3}{2014}-\frac{3}{2015}}\)
=\(\frac{\frac{1}{2012}+\frac{1}{2013}-\frac{1}{2014}}{5\left(\frac{1}{2012}+\frac{1}{2013}-\frac{1}{2014}\right)}-\frac{2\left(\frac{1}{2013}+\frac{1}{2014}-\frac{1}{2015}\right)}{3\left(\frac{1}{2013}+\frac{1}{2014}-\frac{1}{2015}\right)}=\frac{1}{5}-\frac{2}{3}=\frac{3}{15}-\frac{10}{15}=-\frac{7}{15}\)
Ta có:
B=2012/(2013+2014)+2013/(2013+2014)
Xét từng số hạng của B:
2012/(2013+2014)<2012/2013
2013/2013+2014<2013/2014
=>B=2012/(2013+2014)+2013/(2013+2014)<2012/2013+2013/2014=A
=>B<A
Xét N có:
\(N=\frac{2012+2013+2014}{2013+2014+2015}=\frac{2012}{2013+2014+2015}+\frac{2013}{2013+2014+2015}+\frac{2014}{2013+2014+2015}\)
Ta các số hạng của M và N có:
\(\frac{2012}{2013}>\frac{2012}{2013+2014+2015}\) (1)
\(\frac{2013}{2014}>\frac{2013}{2013+2014+2015}\) (2)
\(\frac{2014}{2015}>\frac{2014}{2013+2014+2015}\) (3)
Từ (1);(2);(3) => M > N
1/ Ta có : \(\frac{212121}{353535}=\frac{3.7.10101}{5.7.10101}=\frac{3}{5}=\frac{42}{70}\)
\(\frac{131313}{141414}=\frac{13.10101}{14.10101}=\frac{13}{14}=\frac{65}{70}\)
Vì 42 < 65 => \(\frac{42}{70}<\frac{65}{70}\) => \(\frac{212121}{353535}<\frac{131313}{141414}\)