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\(b,S=\frac{2007}{2008}+\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}\)
\(\text{Ta có: }\frac{2007}{2008}< 1\)
\(\frac{2008}{2009}< 1\)
\(\frac{2009}{2010}< 1\)
\(\frac{2010}{2011}< 1\)
\(\Rightarrow\frac{2007}{2008}+\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}< 1+1+1+1\)
\(\Rightarrow\frac{2007}{2008}+\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}< 4\)
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A=2010/2009+2011/2010+2012/2011+2009/2012=4,00000148
vay A lon hon 4
A>4
a bang 2010/2009cong2012/2011cong2009/2012 bang4,00000148 vay A LON HON 4
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giải giúp mk với mk đang cần gấp lắm!!! Mong các bạn giúp đỡ mk với!!!
\(A=\frac{2010}{2009}+\frac{2011}{2010}+\frac{2012}{2011}+\frac{2009}{2012}=\left(1+\frac{1}{2009}\right)+\left(1+\frac{1}{2010}\right)+\left(1+\frac{1}{2011}\right)+\frac{2009}{2012}>\left(1+\frac{1}{2012}\right)+\left(1+\frac{1}{2012}\right)+\left(1+\frac{1}{2012}\right)+\frac{2009}{2012}=\left(1+1+1\right)+\left(\frac{1}{2012}+\frac{1}{2012}+\frac{1}{2012}+\frac{2009}{2012}\right)=3+1=4\)Vì 1/2009,1/2010,1/2011>1/2012
Vậy A>4
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1.
tong cua hai so la;
425x2=850
vi ab la so co hai chu so nen => 7ab hon ab la 700 don vi
so 7ab la:
(850+700):2=775
=> ab=75
2.
ta co
2010/2011=1-1/2011
2011/2012=1-1/2012
2012/2013=1-1/2013
2013/2014=1-1/2014
vi so bi tru deu la 1 nen ta co:
1/2011>1/2012>1/2013>1/2014
vay 2010/2011<2011/2012<2012/2013<2013/2014
Là sao bn ? bn hỏi rõ hơn đc k ? câu hỏi k rõ ràng cho lắm :v
\(A=\frac{2012.2010+2013}{2011.2011+2012}\)
\(\Rightarrow A=\frac{\left(2011+1\right).\left(2011-1\right)+2013}{2011.2011+2012}\)
\(\Rightarrow A=\frac{2011\left(2011+1\right)-2011-1+2013}{2011.2011+2012}\)
\(\Rightarrow A=\frac{2011^2+2011-2011-1+2013}{2011^2+2012}\)
\(\Rightarrow A=\frac{2011^2-1+2013}{2011^2+2012}\)
\(\Rightarrow A=\frac{2011^2+2012}{2011^2+2012}=1\)
Vậy A = 1