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Ta có: 25/26 = 2525/2626 = 25250/26260
Mà : 25250/26260 < 25251/26261
=> 25/26 < 25251/26261
a)
Ta có:
\(c=25\times26261=25\times\left(26260+1\right)=25\times10\times26\times101+25\)
\(d=26\times25251=26\times\left(25250+1\right)=26\times10\times25\times101+26\)
Vì \(25\times10\times26\times101\) = \(26\times10\times25\times101\) mà \(25< 26\)
=> \(c< d\)
b)
Ta có:
\(b=2022\times2024=2022\times\left(2023+1\right)=2022\times2023+2022\)
\(a=2023\times2023=2023\times\left(2022+1\right)=2023\times2022+2023\)
Vì \(2022\times2023=2023\times2022\) mà \(2022< 2023\)
=> \(b< a\)
a)
a = 53. 571 = 53. (531 + 40) = 53. 531 + 53. 40 = 53. 531 + 53. (10.4)
= 53. 531 + (53. 10). 4 = 53. 531 + 530. 4
b = 57. 531 = (53 + 4). 531 = 531. (53 + 4) = 531. 53 + 531. 4
Vì 530 < 531 nên 530. 4 < 531. 4 do đó 53. 531 + 530. 4 < 531. 53 + 531. 4 hay a < b.
Vậy a < b.
b)
a = 25. 26 261 = 25. (26 260 + 1) = 25. 26 260 + 25. 1 = 25. (10. 2 626) + 25
= (25. 10). 2 626 + 25
= 25. 10. (26. 101) + 25 = 10. 25. 26. 101 + 25;
b = 26. 25 251 = 26. (25 250 + 1) = 26. 25 250 + 26. 1 = 26. (10. 2 525) + 26
= 26. 10. 2 525 + 26 = 26. 10. 25. 101 + 26 = 10. 25. 26. 101 + 26;
Vì 25 < 26 nên 10. 25. 26. 101 + 25 < 10. 25. 26. 101 + 26 hay a < b.
Vậy a < b.
\(a,\dfrac{53}{57}=\dfrac{53.10}{57.10}=\dfrac{530}{570}=1-\dfrac{40}{570}\\ \dfrac{531}{571}=1-\dfrac{40}{571}\\ Vì:\dfrac{40}{570}>\dfrac{40}{571}\Rightarrow1-\dfrac{40}{570}< 1-\dfrac{40}{571}\\ \Leftrightarrow\dfrac{53}{57}< \dfrac{531}{571}\)
a)
\(\frac{64}{85}< \frac{64}{81}< \frac{73}{81}\)
=>\(\frac{64}{85}< \frac{73}{81}\)
b)
\(\frac{25}{26}=\frac{25.1010}{26.1010}=\frac{25250}{26260}\)
Ta có: \(1-\frac{25250}{26260}=\frac{1010}{26260}\)
\(1-\frac{25251}{26261}=\frac{1010}{26261}\)
Vì \(\frac{1010}{26260}>\frac{1010}{26261}\) nên \(\frac{25}{26}< \frac{25251}{26261}\)
a)\(\frac{64}{85}\)<\(\frac{64}{81}\)<\(\frac{73}{81}\)
b)\(\frac{25}{26}\)=\(\frac{25250}{26260}\)=\(1\)- \(\frac{1010}{26260}\)< \(1\)- \(\frac{1010}{26261}\)= \(\frac{25251}{26261}\)
Ta có:
\(\frac{25}{26}=\frac{2525}{2626}=\frac{25250}{26260}\)
Vì \(\frac{25250}{26260}< \frac{25251}{26261}\)
\(\Rightarrow\frac{25}{26}< \frac{25251}{26261}\)
\(\left\{\begin{matrix}A=\frac{25}{26}\\B=\frac{25251}{26261}\end{matrix}\right.\)
\(\frac{25}{26}=\frac{25.1010}{26.1010}=\frac{25250}{26260}\)
\(A-B=\frac{25250}{25250}-\frac{25251}{26261}=\frac{25250.26261-25251.26260}{25250.26261}=\frac{\left(25251-1\right)\left(26260+1\right)-25251.2620}{25250.26261}\)
\(A-B=\frac{25251.26260-2-25251.2620}{25250.26261}=-\frac{2}{25250.26261}< 0\)
\(A-B< 0\Rightarrow A< B\)
Ta có: 1-\frac{25}{26}1−2625=\frac{1}{26}=261
Lại có: 1-\frac{25251}{26261}1−2626125251=\frac{1010}{26261}=262611010
Vậy ta so sánh: \frac{1}{26}261với \frac{1010}{26261}262611010
Quy đồng \frac{1}{26}261ta có: \frac{1}{26}=\frac{1010}{26260}261=262601010
Do 26260 < 26261 \Rightarrow⇒\frac{1010}{26260}>\frac{1010}{26261}262601010>262611010\Rightarrow⇒\frac{1}{26}>\frac{1010}{26261}261>262611010
\Rightarrow\frac{25}{26}< \frac{25251}{26261}⇒2625<2626125251
Duyệt đi, chúc bạn học giỏi!