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Bài làm :
1)\(\frac{3}{2}+\frac{5}{2}-\frac{4}{2}=\frac{3+5-4}{2}=\frac{4}{2}=2\)
2)\(\frac{2}{5}\times\frac{1}{2}\div\frac{1}{3}=\frac{2\times1\times3}{5\times2\times1}=\frac{6}{10}=\frac{3}{5}\)
3)\(\frac{2}{9}\div\frac{9}{2}\times\frac{1}{2}=\frac{2\times2\times1}{9\times9\times2}=\frac{4}{162}=\frac{2}{81}\)
4)\(\left(\frac{4}{11}+\frac{3}{11}\right)\times\frac{2}{6}=\frac{4+3}{11}\times\frac{2}{6}=\frac{7}{11}\times\frac{2}{6}=\frac{7\times2}{11\times6}=\frac{14}{66}=\frac{7}{33}\)
\(a,MSC:3\)
Vì \(2>1\)
\(\Rightarrow\dfrac{2}{3}>\dfrac{1}{3}\)
\(b,MSC:42\\ \dfrac{4}{6}=\dfrac{4.7}{6.7}=\dfrac{28}{42}\\ \dfrac{4}{7}=\dfrac{4.6}{7.6}=\dfrac{24}{42}\)
Vì \(28>24\\ \Rightarrow\dfrac{4}{6}>\dfrac{4}{7}\)
\(c,MSC:22\)
\(\dfrac{6}{11}=\dfrac{6.2}{11.2}=\dfrac{12}{22}=\dfrac{12}{22}\\ \Rightarrow\dfrac{6}{11}=\dfrac{12}{22}\)
\(d,MSC:2\\ 1=\dfrac{2}{2}\)
Vì \(3>2\\ \Rightarrow\dfrac{3}{2}>1\)
\(\frac{3}{2}\)\(+\)\(\frac{5}{2}\)\(-\)\(\frac{4}{2}\)\(=\)\(\left(\frac{3}{2}+\frac{5}{2}\right)-\frac{4}{2}\)
\(=\frac{8}{2}-\frac{4}{2}=\frac{4}{2}=2\)
\(\frac{2}{5}\)\(x\)\(\frac{1}{2}\)\(:\)\(\frac{1}{3}\)\(=\)\(\left(\frac{2}{5}x\frac{1}{2}\right)\)\(:\)\(\frac{1}{3}\)
\(=\)\(\frac{2}{10}\)\(:\)\(\frac{1}{3}\)\(=\frac{2}{10}x\frac{3}{1}\)\(=\frac{6}{10}=\frac{3}{5}\)
3 x \(\frac{4}{11}\) = \(\frac{3}{1}\) x \(\frac{4}{11}\) = \(\frac{12}{11}\)
1 : \(\frac{5}{4}\) = \(\frac{1\times4}{5}\) = \(\frac{4}{5}\)
\(\frac{4}{5}\) x \(\frac{6}{7}\) + \(\frac{2}{3}\) = \(\frac{24}{35}\) + \(\frac{2}{3}\) = \(\frac{142}{105}\)
\(\frac{3}{4}\) + \(\frac{1}{2}\) : \(\frac{5}{6}\) = \(\frac{3}{4}\) + \(\frac{1}{2}\) x \(\frac{6}{5}\) = \(\frac{3}{4}\)+ \(\frac{6}{10}\) \(\frac{27}{20}\)
\(\frac{3}{4}\)+ \(\frac{1}{2}\) = \(\frac{3}{4}\) + \(\frac{2}{4}\)= \(\frac{5}{4}\)
Ta có: \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).....\left(1-\frac{1}{20}\right).\)
\(=\frac{1}{2}-\frac{2}{3}.......\frac{19}{20}\)
\(=\frac{1.2.3....19}{2.3.4...20}=\frac{1}{20}\)
nha, cảm ơn
\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{20}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{19}{20}\)
\(=\frac{1}{20}\)
Dấu . là nhân nha
bài 4:so sánh
5/2 lớn hơn 3/7
4/3 lớn hơn,3/2 lớn hơn
bài 6:rút gọn các phân số sau:
3/9=1/3 9/12=3/4 8/18=4/9 60/36=10/6 17/34=1/2 17/51=1/3 35/100=7/20 25/100=1/4 8/1000=1/125 24/30=4/5 18/54=1/3 72/42=12/7
đay nhé mk chưa làm hết đc bn viết liền quá mk nhìn khó mà mk hỏi bài 7 là nhân hay cộng vậy?
a, \(x\)<\(\frac{3}{4}\)+\(\frac{4}{3}\) <=> \(x\)<\(\frac{25}{12}\)vì x là số tự nhiên => x = 2:x = 1
b,\(\frac{1}{2}\)x\(\frac{1}{3}\)<\(x\)< \(\frac{1}{4}\): \(\frac{1}{8}\)<=> \(\frac{1}{6}\)< x < 2 vì x là số tự nhiên => x = 1 .
Chúc bạn học toots~<>
a) \(\frac{3}{4}\times\frac{5}{6}-\frac{1}{6}\)
\(=\frac{3\times5}{4\times6}-\frac{1}{6}\)
\(=\frac{3\times5}{4\times2\times3}-\frac{1}{6}\)
\(=\frac{5}{8}-\frac{1}{6}\)
\(=\frac{15}{24}-\frac{4}{24}\)
\(=\frac{11}{24}\)
b) \(\frac{1}{2}+\frac{1}{3}\div\frac{1}{4}\)
\(=\frac{1}{2}+\frac{1}{3}\times\frac{4}{1}\)
\(=\frac{1}{2}+\frac{1\times4}{3\times1}\)
\(=\frac{1}{2}+\frac{4}{3}\)
\(=\frac{3}{6}+\frac{8}{6}\)
\(=\frac{11}{6}\)
Theo ý e bảo chỉ làm 3 dòng thôi nên a rút gọn phép tính lại:
a) \(\frac{3}{4}\times\frac{5}{6}-\frac{1}{6}\)
\(=\frac{5}{8}-\frac{1}{6}\)
\(=\frac{15}{24}-\frac{4}{24}\)
\(=\frac{11}{24}\)
b) \(\frac{1}{2}+\frac{1}{3}\div\frac{1}{4}\)
\(=\frac{1}{2}+\frac{4}{3}\)
\(=\frac{3}{6}+\frac{8}{6}\)
\(=\frac{11}{6}\)