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a) \(\dfrac{2727-101}{3.303+404}=\dfrac{2626}{909+404}=\dfrac{2626}{1313}=2\)
b) \(\dfrac{8.9-4.15}{12.7-180}=\dfrac{72-60}{84-180}=\dfrac{12}{-96}=\dfrac{-1}{8}\)
c) \(\dfrac{-19}{3^2.7.11}=\dfrac{-19}{9.7.11}=\dfrac{-19}{63.11}=\dfrac{-19}{693}\)
d) \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\dfrac{2^{12}.3^{10}+120.6^9}{2^{12}.3^{12}-6^{11}}=\dfrac{2^2.6^{10}+20.6.6^9}{6^{12}-6^{11}}=\dfrac{4.6^{10}+20.6^{10}}{6^{11}\left(6-1\right)}=\dfrac{\left(4+20\right).6^{10}}{5.6^{11}}=\dfrac{24}{30}=\dfrac{4}{5}\)
\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{15}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{15}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}\left(3^5+5\right)}{2^{11}.3^{11}\left(2.3-1\right)}\)
cho mk sửa lại xíu:
\(\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.5}=\frac{2.6}{3.5}=\frac{12}{15}=\frac{4}{5}\)
mk sai xíu. hihi, học tốt nhé !
A=(2^2)^6.(3^2)^5+2^9.3^9.2^3.5.3/2^12.3^10+2^11.3^11
=2^12.3^10+2^12.3^10.5/2^12.3^10+2^11.3.3^10
=2^12.3^10.(1+5)/2^11.3^10.(2+3)
=2^11.2.6/2^11.5
=12/5