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\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
a: 27/-180=-27/180=-3/20=-21/140
-6/-35=6/35=24/120
-3/-28=3/28=15/140
b: \(\dfrac{3\cdot4+3\cdot7}{6\cdot5+9}=\dfrac{3\left(4+7\right)}{30+9}=\dfrac{11}{13}=\dfrac{2849}{13\cdot259}\)
\(\dfrac{6\cdot9-2\cdot17}{63\cdot6-119}=\dfrac{54-34}{259}=\dfrac{20}{259}=\dfrac{260}{259\cdot13}\)
\(\dfrac{3\cdot4+3\cdot7}{6\cdot5+9}=\dfrac{3\cdot11}{30+9}=\dfrac{33}{39}=\dfrac{11}{13}=\dfrac{77}{91}\)
\(\dfrac{6\cdot9-2\cdot17}{63\cdot3-119}=\dfrac{54-34}{189-119}=\dfrac{20}{70}=\dfrac{2}{7}=\dfrac{26}{91}\)
\(\frac{3.4+3.7}{6.5+9}\)và \(\frac{6.9-2.17}{63.3-119}\)
\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
\(\frac{6.9-2.17}{63.3-119}=\frac{54-54}{63.3-11}=0\)
\(\frac{3\cdot4+3\cdot7}{6\cdot5+9}\)
\(=\frac{3\left(4+7\right)}{3\cdot2\cdot5+3\cdot3}=\frac{3\cdot11}{3\left(10+3\right)}\)
\(=\frac{11}{13}\)
\(\frac{6\cdot9-2.17}{63\cdot3-119}\)
\(=\frac{3\cdot2\cdot3\cdot3-2\cdot17}{3^2\cdot7\cdot3-7\cdot17}=\frac{2\cdot\left(27-17\right)}{7\left(27-17\right)}\)
\(=\frac{2}{7}\)
Ta có
\(\frac{11}{13}\)và \(\frac{2}{7}\)
\(\Rightarrow\frac{77}{91}=\frac{26}{91}\)