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=5^2.3^11.2^11.2^8.2^2.3^2.3^6.2^12.3^2.5^2/2.3^12.2^12.2^4.5^4-3^8.3^3.2^6.5
ban nhom cac so co cung co so o tu va mau thanh cac nhom va rut gon
tử số : 2.4 + 4.8 + 8.12 + 12.16 + 16.20
= 2.(1.2+2.4+4.6+6.8+8.10)
ta được 2. A=( 1.2+2.4+4.6+6.8+8.10) / ( 1.2+2.4+4.6+6.8+8.10)
=> A=2
H=\(\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{1\cdot3\cdot6+2\cdot6\cdot12+3\cdot9\cdot18+5\cdot15\cdot30}=\frac{1.2.3+2^3.\left(1.2.3\right)+3^3.\left(1.2.3\right)+5^3.\left(1.2.3\right)}{1.3.6+2^3.\left(1.3.6\right)+3^3.\left(1.3.6\right)+5^3.\left(1.3.6\right)}=\frac{1.2.3.\left(1+2^3+3^3+5^3\right)}{1.3.6.\left(1+2^3+3^3+5^3\right)}=\frac{2}{6}=\frac{1}{3}\)
\(\frac{2.4.10+4.6.8+14.16.20}{3.6.15+6.9.12+21.24.30}=\frac{2\left(1.2.5\right)+2\left(2.3.4\right)+2\left(7.8.9\right)}{3\left(1.2.5\right)+3\left(2.3.4\right)+3\left(7.8.9\right)}=\frac{2\left(1.2.5+2.3.4+7.8.9\right)}{3\left(1.2.5+2.3.4+7.8.9\right)}=\frac{2}{3}.\)
Hacker 2k6
Trả lời:
\(\frac{2.4.10+4.6.8+14.16.20}{3.6.15+6.9.12+21.24.30}\)
\(=\frac{2\left(1.2.5\right)+2\left(2.3.4\right)+2\left(7.8.10\right)}{3\left(1.2.5\right)+3\left(2.3.4\right)+3\left(7.8.10\right)}\)
\(=\frac{2\left(1.2.5+2.3.4+7.8.10\right)}{3\left(1.2.5+2.3.4+7.8.10\right)}\)
\(=\frac{2}{3}\)(Vì\(1.2.5+2.3.4+7.8.10\ne0\))
Hok tốt!
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\(\frac{5^2.3^{11}.2^{11}.2^8+2^2.3^2.3^2.5^2}{2.2^{12}.3^{12}.2^4.5^4-3^8.2^{18}.3^3.5^3}\)
\(=\frac{5^2.3^{11}.2^{19}+2^2.3^4.5^2}{2^{17}.3^{12}.5^4-3^{11}.2^{18}.5^3}\)
\(=\frac{5^2.3^4.2^2.\left(3^7.2^{17}+1\right)}{2^{17}.3^{11}.5^3.\left(3.5-2\right)}=\frac{3^7.2^{17}}{2^{15}.3^7.5}+\frac{1}{2^{15}.3^7.5}=\frac{4}{5}+\frac{1}{2^{15}.3^7.5}\)