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\(\dfrac{x}{x+2}+\dfrac{7x-16}{\left(x+2\right)\left(4x-7\right)}\left(dkxd:x\ne-2;x\ne\dfrac{7}{4}\right)\)
\(=\dfrac{x\left(4x-7\right)+7x-16}{\left(x+2\right)\left(4x-7\right)}\)
\(=\dfrac{4x^2-7x+7x-16}{\left(x+2\right)\left(4x-7\right)}\)
\(=\dfrac{4x^2-16}{\left(x+2\right)\left(4x-7\right)}\)
\(=\dfrac{4\left(x^2-4\right)}{\left(x+2\right)\left(4x-7\right)}\)
\(=\dfrac{4\left(x-2\right)\left(x+2\right)}{\left(x+2\right)\left(4x-7\right)}\)
\(=\dfrac{4\left(x-2\right)}{4x-7}\)
\(=\dfrac{4x-8}{4x-7}\)
===============================
\(\dfrac{x}{x-2}+\dfrac{2}{2-x}\left(dkxd:x\ne2\right)\)
\(=\dfrac{x}{x-2}-\dfrac{2}{x-2}\)
\(=\dfrac{x-2}{x-2}\)
\(=1\)
a, \(\left(\dfrac{x}{x^2-49}-\dfrac{x-7}{x^2+7x}\right):\dfrac{2x-7}{x^2+7x}+\dfrac{x}{7-x}\)
\(=\left[\dfrac{x^2}{x\left(x-7\right)\left(x+7\right)}-\dfrac{\left(x-7\right)^2}{x\left(x+7\right)\left(x-7\right)}\right].\dfrac{x\left(x+7\right)}{2x-7}+\dfrac{x}{7-x}\)
\(=\left[\dfrac{x^2-\left(x-7\right)^2}{x\left(x-7\right)\left(x+7\right)}\right].\dfrac{x\left(x+7\right)}{2x-7}+\dfrac{x}{7-x}\)
\(=\left[\dfrac{\left(x-x+7\right)\left(x+x-7\right)}{x\left(x-7\right)\left(x+7\right)}\right].\dfrac{x\left(x+7\right)}{2x-7}+\dfrac{x}{7-x}\)
\(=\dfrac{7\left(2x-7\right)}{x\left(x-7\right)\left(x+7\right)}.\dfrac{x\left(x+7\right)}{2x-7}+\dfrac{x}{7-x}\)
\(=\dfrac{7}{x-7}+\dfrac{x}{7-x}\)
\(=\dfrac{7\left(7-x\right)+x\left(x-7\right)}{\left(x-7\right)\left(7-x\right)}=\dfrac{49-7x+x^2-7x}{7x-x^2-49+7x}\)
\(=\dfrac{49-14x+x^2}{14x-x^2-49}=\dfrac{-\left(14-x^2-49\right)}{14x-x^2-49}=-1\)
\(\Rightarrow\)Giá trị biểu thức trên không phụ thuộc vào biến
\(\Rightarrowđpcm\)
b, tương tự
Bạn chỉ cần tính ra thôi .
+ Nếu kết quả rút gọn có x thì kết luận giá trị của biểu thức phụ thuộc vào giá trị của biến .
+ Nếu kết quả rút gọn không có x thì kết luận giá trị của biểu thức không phụ thuộc vào giá trị của biến .
Chúc bạn làm bài tốt nha .
b: \(\Leftrightarrow\dfrac{7x+10}{x+1}\left(x^2-x-2-2x^2+3x+5\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(-x^2+2x+3\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(x^2-2x-3\right)=0\)
=>(7x+10)(x-3)=0
hay \(x\in\left\{-\dfrac{10}{7};3\right\}\)
d: \(\Leftrightarrow\dfrac{13}{2x^2+7x-6x-21}+\dfrac{1}{2x+7}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{\left(2x+7\right)}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow26x+91+x^2-9-12x-14=0\)
\(\Leftrightarrow x^2+14x+68=0\)
hay \(x\in\varnothing\)
a: \(\Leftrightarrow\dfrac{7x+10}{x+1}\left(x^2-x-2-2x^2+3x+5\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(-x^2+2x+3\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\cdot\left(x^2-2x-3\right)=0\)
=>(7x+10)(x-3)=0
=>x=3 hoặc x=-10/7
b: \(\Leftrightarrow\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{2x+7}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow13\left(x+3\right)+x^2-9-12x-42=0\)
\(\Leftrightarrow x^2-12x-51+13x+39=0\)
\(\Leftrightarrow x^2+x-12=0\)
=>(x+4)(x-3)=0
=>x=-4
Lời giải:
ĐKXĐ:.....
Ta có: \(\frac{x+5}{x(2x-5)+2}+\frac{x+2}{x(2x-7)+3}=\frac{2x+7}{2x^2-7x+3}\)
\(\Leftrightarrow \frac{x+5}{x(2x-5)+2}=\frac{2x+7}{2x^2-7x+3}-\frac{x+2}{2x^2-7x+3}\)
\(\Leftrightarrow \frac{x+5}{x(2x-5)+2}=\frac{2x+7-(x+2)}{2x^2-7x+3}\)
\(\Leftrightarrow \frac{x+5}{x(2x-5)+2}=\frac{x+5}{2x^2-7x+3}\)
\(\Leftrightarrow (x+5)\left(\frac{1}{x(2x-5)+2}-\frac{1}{2x^2-7x+3}\right)=0\)
TH1: \(x+5=0\Leftrightarrow x=-5\) (thỏa mãn)
TH2: \(\frac{1}{x(2x-5)+2}-\frac{1}{2x^2-7x+3}=0\)
\(\Leftrightarrow x(2x-5)+2=2x^2-7x+3\)
\(\Leftrightarrow -5x+2=-7x+3\)
\(\Leftrightarrow 2x=1\Leftrightarrow x=\frac{1}{2}\). Thử lại thây mẫu số bằng 0 (không thỏa mãn ĐKXĐ)
Vậy PT có nghiệm duy nhất \(x=-5\)
\(1\text{)}\left(x-5\right)^2+3\left(x-5\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(x-5+3\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
\(2\text{)}\dfrac{2x-1}{3}-\dfrac{5x+2}{7}=x+13\)
\(\Leftrightarrow\dfrac{7\left(2x-1\right)-3\left(5x+2\right)}{21}=\dfrac{21\left(x+13\right)}{21}\)
\(\Leftrightarrow14x-7-15x-6=21x+273\)
\(\Leftrightarrow-x-13=21x+273\)
\(\Leftrightarrow-22x=286\)
\(\Rightarrow x=-\dfrac{286}{22}=-\dfrac{143}{11}\)
\(3\text{)}\dfrac{x-1}{x+2}-\dfrac{x}{x-2}=\dfrac{7x-6}{4-x^2}\left(đk:x\ne\pm2\right)\)
\(\Leftrightarrow\dfrac{x-1}{2+x}+\dfrac{x}{2-x}=\dfrac{7x-6}{4-x^2}\)
\(\Leftrightarrow\dfrac{\left(x-1\right)\left(2-x\right)+x\left(2+x\right)}{4-x^2}=\dfrac{7x-6}{4-x^2}\)
\(\Leftrightarrow2x-x^2-2+x+2x+x^2=7x-6\)
\(\Leftrightarrow x-2=7x-6\)
\(\Leftrightarrow-6x=-4\)
\(\Rightarrow x=\dfrac{2}{3}\)
a: \(\Leftrightarrow7\left(7-3x\right)+12\left(5x+2\right)=84\left(x+13\right)\)
\(\Leftrightarrow49-21x+60x+24=84x+1092\)
\(\Leftrightarrow39x-84x=1092-73\)
=>-45x=1019
hay x=-1019/45
b: \(\Leftrightarrow21\left(x+3\right)-14=4\left(5x+9\right)-7\left(7x-9\right)\)
=>21x+63-14=20x+36-49x+63
=>21x+49=-29x+99
=>50x=50
hay x=1
c: \(\Leftrightarrow7\left(2x+1\right)-3\left(5x+2\right)=21x+63\)
=>14x+7-15x-6-21x-63=0
=>-22x-64=0
hay x=-32/11
d: \(\Leftrightarrow35\left(2x-3\right)-15\left(2x+3\right)=21\left(4x+3\right)-17\cdot105\)
=>70x-105-30x-45=84x+63-1785
=>40x-150-84x+1722=0
=>-44x+1572=0
hay x=393/11
\(A=\left(\dfrac{x}{x^2-49}-\dfrac{x-7}{x^2+7x}\right):\dfrac{2x-7}{x^2+7x}+\dfrac{x}{7-x}\)
\(A=\left(\dfrac{x}{\left(x-7\right)\left(x+7\right)}-\dfrac{x-7}{x\left(x+7\right)}\right):\dfrac{2x-7}{x^2+7x}+\dfrac{x}{7-x}\)
\(A=\dfrac{x^2-\left(x-7\right)^2}{x\left(x-7\right)\left(x+7\right)}\times\dfrac{x^2+7x}{2x-7}+\dfrac{x}{7-x}\)
\(A=\dfrac{x^2-x^2+14x-49}{x\left(x-7\right)\left(x+7\right)}\times\dfrac{x\left(x+7\right)}{2x-7}+\dfrac{x}{7-x}\)
\(A=\dfrac{7\left(2x-7\right)}{x\left(x-7\right)\left(x+7\right)}\times\dfrac{x\left(x+7\right)}{2x-7}+\dfrac{x}{7-x}\)
\(A=\dfrac{7}{x-7}-\dfrac{x}{x-7}\)
\(A=\dfrac{7-x}{x-7}\)
\(A=-\dfrac{7-x}{7-x}\)
\(A=-1\)
\(A=\left(\dfrac{x}{x^2-49}-\dfrac{x-7}{x^2+7x}\right):\dfrac{2x-7}{x^2+7x}+\dfrac{x}{7-x}\)
\(A=\left(\dfrac{x}{\left(x-7\right)\left(x+7\right)}-\dfrac{x-7}{x\left(x+7\right)}\right).\dfrac{x^2+7x}{2x-7}-\dfrac{x}{x-7}\)
\(A=\dfrac{x^2-\left(x-7\right)^2}{x\left(x-7\right)\left(x+7\right)}.\dfrac{x\left(x+7\right)}{2x-7}-\dfrac{x}{x-7}\)
\(A=\dfrac{\left(x-x+7\right)\left(x+x-7\right)}{x-7}.\dfrac{1}{2x-7}-\dfrac{x}{x-7}\)
\(A=\dfrac{\left(x-x+7\right)\left(2x-7\right)}{x-7}.\dfrac{1}{2x-7}-\dfrac{x}{x-7}\)
\(A=\dfrac{7}{x-7}-\dfrac{x}{x-7}\)
\(A=\dfrac{7-x}{x-7}=\dfrac{-\left(x-7\right)}{x-7}=-1\)