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\(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)
\(\frac{3600-75}{8400-175}=\frac{75\left(48-1\right)}{35\left(240-5\right)}=\frac{15\cdot47}{7\cdot235}=\frac{3\cdot5\cdot47}{7\cdot5\cdot47}=\frac{3}{7}\)
g, \(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)
h, \(\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3}{7}\)
a, \(\dfrac{990}{2610}=\dfrac{11}{29}\)
b) \(\dfrac{3600-75}{8400-175}=\dfrac{3}{7}\)
c) \(\dfrac{9^{14}\cdot25^5\cdot8^7}{18^{12}\cdot625^5\cdot24^3}=\dfrac{3}{25}\)
ừa, nhưng mik còn những câu sau khó hơn nhưng mỏi tay quá nên tí gửi tiếp!
a) \(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)\)
=\(\left(2^3.9^4+9^3.9.5\right):9^2\left(10-1\right)\)
= \(\left(8-9^4+9^4.5\right):9^2.9\)
=\(9^4\left(8-5\right):9^3\)
=\(9^4.3:9^3\)
=\(9^4:9^3.3\)
=\(9.3\)
=\(27\)
Rút gọn
A, \(\dfrac{125}{1000}\)
\(\dfrac{125}{1000}=\dfrac{125:125}{1000:125}=\dfrac{1}{8}\)
B, \(\dfrac{3600-75}{4800-175}\)
\(\dfrac{3600-75}{4800-175}=\dfrac{3525}{4625}\)
\(\Rightarrow\dfrac{3525}{4625}=\dfrac{3525:25}{4625:25}=\dfrac{141}{185}\)
C, \(\dfrac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}\)
\(\dfrac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\dfrac{3^{10}.\left(-5\right)^{20}.\left(-5\right)}{\left(-5\right)^{20}.3^{10}.3^2}=\dfrac{\left(-5\right)}{3^2}=\dfrac{-5}{9}\)