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a)Ư(6)={1;2;3;6}
Ư(9)={1;3;9}
Ư(6;9)={1;3}
b)Ư(7)={1;7}
Ư(8)={1;2;4;8}
ƯC(7;8)=1
c)Ư(4)={1;2;4}
Ư(6)={1;2;3;6}
Ư(8)={1;2;4;8}
ƯC(4;6;8)={1;2
ƯC
a) Ư (6) = {1; 2; 3; 6}
Ư (9) = {1, 3, 9}
ƯC (6, 9) = {1; 3}.
b) Ư (7) = {1; 7}
Ư (8) = {1; 2; 4; 8}
ƯC (7, 8) = {1}.
c) ƯC (4, 6, 8) = {1, 2}.
a) Ư (6) = {1; 2; 3; 6}, Ư (9) = {1, 3, 9}, ƯC (6, 9) = {1; 3}.
b) Ư (7) = {1; 7}, Ư (8) = {1; 2; 4; 8}, ƯC (7, 8) = {1}.
c) ƯC (4, 6, 8) = {1, 2}.
a) Ư(6) = {1;2;3;6}
Ư(9) = {1;3;9}
ƯC(6,9) = {1;3}
b) Ư(7) = {1;7}
Ư(8) = {1;2;4;8}
ƯC(7;8) = {1}
c) ƯC(4;6;8) = { 1;2}
Viết các tập hợp :
a) Ư(6), Ư(9), ƯC(6,9);
b) Ư(7), Ư(8), ƯC(7,8);
c) ƯC(4; 6; 8)
GIẢI CHI TIẾT NỮA NHÉ!
\(\text{Ư}\left(6\right)=\left\{1;2;3;6\right\}\)
\(\text{Ư}\left(9\right)=\left\{1;3;9\right\}\)
\(\text{Ư}C\left(6;9\right)=\left\{3\right\}\)
a: \(Ư\left(16\right)=\left\{1;2;4;8;16\right\}\)
\(Ư\left(24\right)=\left\{1;2;3;4;6;8;12;24\right\}\)
\(ƯC\left(16;24\right)=\left\{1;2;4;8\right\}\)
b: \(Ư\left(20\right)=\left\{1;2;4;5;10;20\right\}\)
\(Ư\left(32\right)=\left\{1;2;4;8;16;32\right\}\)
\(ƯC\left(20;32\right)=\left\{1;2;4\right\}\)
a) Ư(8) = {1;2;4;8}; Ư(12) = {1;2;3;4;6;12} => ƯC(8;12) = {1;2;4;}
b) Ư(24) = {1;2;3;4;6;8;12;24}; Ư(32) = {1;2;4;8;16;32} => ƯC(24; 32) = {1;2;4;8;}
c) Ư(7) = {1;7} ; Ư(10) = {1;2;5;10} => ƯC(7;10) = {1}
d) 8 = 23; 10 = 2.5 => BCNN (8;10) = 23.5 = 40 => BC(8;10) = B(40) = {0;40;80;...}
e) 25 = 52 => BCNN(2;3;25) = 2.3.52 = 150 => BC (2;3;25) = B(150) = {0;150; 300; ...}
2) N = {0;1;2;3;...}; N* = {1;2;3;....} => N giao N* = {1;2;3;...} = N*
a) Ư(8) = {1;2;4;8}; Ư(12) = {1;2;3;4;6;12} => ƯC(8;12) = {1;2;4;}
Vâu b,c,d,e tương tự nha bn
2) N = {0;1;2;3;...}; N* = {1;2;3;....} => N giao N* = {1;2;3;...} = N*
hok tốt
Ư(48)=[1;2;3;4;6;8;12;16;24;48]
Ư(80)=[1;2;4;5;8;10;16;20;40;80]
Ư(72)=[1;2;3;4;6;8;9;12;18;24;36;72]
ƯC(48,80,72)=[1;2;4;8]