Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a/\(^{2867971991^{-10}}\)
b/\(^{1125899907^{-55}}\)
c/\(^{1693508781^{-05}}\)
d/\(^{2867971991^{-10}}\)
1.a) \(\left(\frac{3}{5}\right)^{15}:\left(\frac{9}{25}\right)^5=\frac{3^{15}}{5^{15}}.\frac{5^{10}}{3^{10}}=\frac{3^5}{5^5}=\left(\frac{3}{5}\right)^5\)
b)\(\left(\frac{2}{3}\right)^{10}:\left(\frac{4}{9}\right)^4=\frac{2^{10}}{3^{10}}.\frac{3^8}{2^8}=\frac{2^2}{3^2}=\left(\frac{2}{3}\right)^2\)
2.
a)\(2^x=4\Rightarrow2^x=2^2\Rightarrow x=2\)
b)\(x^3=-27\Rightarrow x^3=-3^3\Rightarrow x=-3\)
c)\(x^2=16\Rightarrow x=\pm4\)
d)\(\left(x+1\right)^2=9\Rightarrow\hept{\begin{cases}x+1=3\Rightarrow x=2\\x+1=-3\Rightarrow x=-4\end{cases}}\)
\(a,\left(\frac{1}{16}\right)^3:\left(\frac{1}{8}\right)^2=\frac{1}{16^3}.8^2=\frac{\left(2^3\right)^2}{\left(2^4\right)^3}=\frac{2^{3.2}}{2^{4.3}}=\frac{2^6}{2^{12}}=\frac{1}{2^6}\)
\(b,\left(\frac{1}{9}\right)^{25}:\left(\frac{1}{3}\right)^{30}=\frac{1}{9^{25}}.3^{30}=\frac{3^{30}}{\left(3^2\right)^{25}}=\frac{3^{30}}{3^{50}}=\frac{1}{3^{20}}\)