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a) \(\frac{16.64.8^2}{4^3.2^5.16}=\frac{16.4^3.\left(2^3\right)^2}{4^3.2^5.16}=\frac{16.4^3.2^6}{4^3.2^5.16}=2\)
\(\frac{64^2.81^3.34}{2^{13}.3^9.17}=\frac{\left(2^6\right)^2.\left(3^4\right)^3.2.17}{2^{13}.3^9.17}=\frac{2^{13}.3^{12}.17}{2^{13}.3^9.17}=3^3=27\)
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a) \(\frac{18^4.3^2.8^3}{27^3.16^2}=\frac{\left(2.3^2\right)^4.3^2.\left(2^3\right)^3}{\left(3^3\right)^3.\left(2^4\right)^2}=\frac{2^4.2^9.3^8.3^2}{3^9.2^8}=\frac{2^{13}.3^{10}}{3^9.2^8}=3.2^5=96\)
b) \(\frac{35^5.9^3.8^5}{81^4.32^5}=\frac{35^5.\left(3^2\right)^3.\left(2^3\right)^5}{\left(3^4\right)^4.\left(2^5\right)^5}=\frac{35^5.3^6.2^{15}}{3^{16}.2^{25}}=\frac{35^5}{3^{10}.2^{10}}=\frac{35^5}{6^{10}}\)
c) \(\frac{48^5.18^2}{81^2.34^4}=\frac{\left(2^4.3\right)^5.\left(2.3^2\right)^2}{\left(3^4\right)^2.\left(2.17\right)^4}=\frac{2^{20}.3^5.2^2.3^4}{3^8.2^4.17^4}=\frac{2^{22}.3^9}{3^8.2^4.17^4}=\frac{2^{18}.3}{17^4}\)
d) \(\frac{54^7.27^3.16^2}{243^2.64^3}=\frac{\left(2.3^3\right)^7.\left(3^3\right)^3.\left(2^4\right)^2}{\left(3^5\right)^2.\left(2^6\right)^3}=\frac{2^7.3^{21}.3^9.2^8}{3^{10}.2^{18}}=\frac{2^{15}.3^{30}}{3^{10}.2^{18}}=\frac{3^{20}}{2^3}\)
[3517:3514+{43.53-(134-123)2}2]
= [ 3517-14 + { 64 . 125 - 112 }2 ]
= [ 353 + { 8000 - 121 }2 ]
= [ 42875 + 78802 ]
= [ 42875 + 62094400 ]
= 62137275
\(34+2^3-\left(-81\right)=34+8+81=123\)
\(14+\left(17\right)+\left(-9^2\right)-35=14+17-81-35=-85\)
34 + 2^3 - ( - 81 ) = 34 + 8 - ( -81 ) = 42 - ( - 81) = 42 + 81 = 123
14 + 17 + (- 81 ) - 35 = 31 + (-81) - 35 = -50 - 35 = -85