Question

[Fan Kpop]

Tính xem A gấp mấy lần B

a/ A=3,4 . 10^-8; B= 34.10^-9

b/ A=10^-4 +10^-3 +10^-2; B=10^-9

Answer 1

[Bùi Hoàng Linh Chi]

a) Ta có: B=34.10\(^{-9}\)=34.\(\frac{1}{10^9}\)=34.\(\frac{1}{10}\).\(\frac{1}{10^8}\)=3,4.10\(^{-8}\)

Vậy A=B

b) Ta có: A=10\(^{-4}\)+10\(^{-3}\)+10\(^{-2}\)=0,0111

B=10\(^{-9}\)=\(\frac{1}{10^9}\)=\(\frac{1}{1000000000}\)=0,000000001

\(\Rightarrow\)A= 11100000B