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a) 232 - (3x + 2).5 = 23.52
232 - (3x + 2).5 = 8.25
232 - 5.(3x + 2) = 200
-5.(3x + 2) = 200 - 232
-5.(3x + 2) = -32
3x + 2 = (-32) : (-5)
3x + 2 = 32/5
3x = 32/5 - 2
3x = 22/5
x = 22/5 : 3
x = 22/15
\(a)232-\left(3x+2\right).5=2^3.5^2\)
\(\Leftrightarrow232-\left(3x+2\right).5=200\)
\(\Leftrightarrow\left(3x+2\right).5=32\)
\(\Leftrightarrow3x+2=6.4\)
\(\Leftrightarrow3x=4.4\)
\(\Leftrightarrow\frac{22}{15}\)
\(b)3.5^x-10^0=74\)
\(\Leftrightarrow3.5^x=75\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
\(\Leftrightarrow x=2\)
\(c)4^{2x+4}=64\)
\(\Leftrightarrow4^{2x+4}=4^3\)
\(\Leftrightarrow2x+4=3\)
\(\Leftrightarrow x=-\frac{1}{2}\)
\(d)5^{x-1}+5^x=100\)
\(\Leftrightarrow5^x.\frac{1}{5}+5^x=100\)
\(\Leftrightarrow5^x\left(\frac{1}{5}+1\right)=100\)
\(\Leftrightarrow5^x=\frac{250}{3}\)
Chưa nghĩ ra. Các câu khác tương tự như các câu trên.
\(\frac{\left(-2\right)^3.3^3.5^3.7.8}{3.5^3.2^4.42}\)
\(=\frac{-8.27.125.7.8}{3.125.16.42}\)
\(=\frac{-8.3.9.125.7.8}{3.125.8.2.7.6}\)
\(=\frac{-72}{12}\)
\(=-6\)
a. \(3.5^2+15.2^2-26:2\)
\(=3.25+15.4-26:2\)
\(=75+60-13\)
\(=122\)
b. \(5^3.2-100:4+2^3.5\)
\(=125.2-100:4+8.5\)
\(=250-25+40\)
\(=265\)
c. \(6^2:9+50.2-3^3.3\)
\(=36:9+50.2-27.3\)
\(=4+100-81\)
\(=23\)
d. \(3^2.5+2^3.10-81:3\)
\(=9.5+8.10-81:3\)
\(=45+80-27\)
\(=98\)
e. \(5^{13}:5^{10}-25.2^2\)
\(=5^3-25.4\)
\(=125-100\)
\(=25\)
f. \(20:2^2+5^9:5^8\)
\(=20:4+5\)
\(=5+5=10\)
P = \(\frac{5.3^{11}+4.3^{12}}{3^9.5^2-3^9.2^2}\)
= \(\frac{\left(5+4.3\right).3^{11}}{3^9.\left(5^2-2^2\right)}\)
=\(\frac{17.3^{11}}{3^9.21}\)
= \(\frac{17.3^2}{7.3}\)
= \(\frac{17.3}{7}=\frac{51}{7}\)
\(4^2-2^2.3+8.5^0\)
\(=16-4.3+8.1\)
\(=12\)
\(5^4.\left[8^2:4^2.\left(2^3+10^0\right)\right]\)
\(=625.\left[64:16.\left(8+1\right)\right]\)
\(=625.\left(64:16.9\right)\)
\(=22500\)
\(11^2.5^3-11^2.25\)
\(=11^2.\left(5^3-25\right)\)
\(=121.\left(125-25\right)\)
\(=12100\)
học tốt
a) 3x52+15x22-26:3
=3x25+15x4-26/3
=75+60-26/3
=135-26/3
=379/3
b) 53x2-100:4+23x5
=125x2-25+8x5
=250-25+40
=225+40
=265