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Ta có : S = (-1)+2+(-3)+4+(-5)+...+(-99)+100
= -1 + (-1) + (-1) +...+ (-1) (50 số -1)
= -50
số số hạng là:(100-1):1+1=100 số
S=-1+(-1)+..+(-1)=-50
a, ( 1/2 + 1) . ( 1/3 + 1) . (1/4 + 1) ... ( 1/999 + 1)
= 3/2 . 4/3 . 5/4 . 1000/999
= 1/2 . 1/1 . 1/1 ... 1000/1
= 1000/2
= 500
b, (1/2-1) . (1/3-1) . (1/4-1) ... (1/1000-1)
= -1/2 . (-2)/3 . (-3)/4 ... (-999)/1000
= (-1)/1 . (-1)/1 . (-1)/1 ... (-1)/1000
= (-1)/1000
c, 3/2^2 . 8/3^2 . 15/4^2 ... 99/10^2
= 1.3/2.2 * 2.4/3.3 * 3.5/4.4***9.11/10.10
=( 1.2.3...99).(3.4.5...11)/(2.3.4....10).(2.3.4...10)
= 1.11/2.10
= 11/20
\(C=2+2^2+...+2^{100}\)
\(2C=2^2+2^3+2^4+...+2^{101}\)
\(2C-C=\left(2^2+2^3+2^4+...+2^{101}\right)-\left(2+2^2+2^3+...+2^{100}\right)\)
\(C=2^{101}-2\)
Giải:
Ta có:2C=2²+2³+........+2^100+2^101
_
C=2+2²+..........+2^100
=>C=2^101-2
HOK TỐT
\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}.........\frac{899}{30^2}\)
A= \(\frac{1.3.2.4.3.5...29.31}{2.2.3.3...30.30}\)
A=\(\frac{\left(2.3...29.30\right)\left(3.4.5...29.31\right)}{\left(2.3.4...30\right)\left(2.3.4...30\right)}\)
A=\(\frac{31}{2.30}\)
A=\(\frac{31}{60}\)
\(75\%+1,1:\left(\frac{2}{5}-1\frac{1}{2}\right)-\left(\frac{1}{3}\right)^2\)
\(=\frac{3}{4}+\frac{11}{10}:\left(\frac{2}{5}-\frac{3}{2}\right)-\frac{1}{9}\)
=\(\frac{3}{4}+\frac{11}{10}:\frac{-11}{10}-\frac{1}{9}\)
\(=\frac{3}{4}+\left(-1\right)-\frac{1}{9}\)
\(=\frac{27}{36}+\left(\frac{-36}{36}\right)-\frac{4}{36}\)
\(=\frac{-13}{36}\)
chúc bạn học tốt
\(\frac{x}{3}=\frac{2}{3}+\frac{-1}{7}\)
\(\Rightarrow\frac{x}{3}=\frac{2}{3}-\frac{-1}{7}\)
\(\Rightarrow\frac{x}{3}=\frac{-17}{7}\)
\(\Rightarrow x=17\)
A=1.2+2.3+3.4+....................+49.50
3A=1.2.3+2.3.3+3.4.3+.......+49.50.3
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+..........+49.50.(51-48)
3A=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-.............-48.49.50+49.50.51
3A=49.50.51
A=\(\frac{49.50.51}{3}\)
A=41650
Chúc bn học tốt
A=1*2+2*3+..+49*50
3A=1*2*3-2*3(4-1)+..+49*50(51-48)
3A=1*2*3+2*3*4-1*2*3+3*4*5-2*3*4+...+49*50*51-48*49*50
3A=49*50*51
a=49*50*51/3