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x = 0,031;0,032;0,033;0,034;0,035;0,036;0,037;0,038;0,039
\(8,75\times x+1,25\times x=20\)
\(\left(8,75+1,25\right)\times x=20\)
\(10\times x=20\)
\(x=20:10\)
\(x=2\)
Vậy \(x=2\)
Cjhucs bạn học tốt !!!
8,75x X + 1,25 x X = 20
X x ( 8,75 + 1,25 ) = 20
X x 10 = 20
X = 20 : 10
X = 2 Vậy X= 2
x x 9,99 + x : 100 = 9,8
x x 9,99 + x x \(\frac{1}{100}\)= 9,8
x x ( 9,99 + \(\frac{1}{100}\)) = 9,8
x x ( 9,99 + 0,01 ) = 9,8
x x 10 = 9,8
x = 9,8 : 10
x = 0,98
\(x\times9,99+x\div100=9,8\)
\(\Rightarrow x\times9,99+x\times\frac{1}{100}=9,8\)
\(\Rightarrow x\times\left(9,99+\frac{1}{100}\right)=9,8\)
\(\Rightarrow x\times10=9,8\)
\(\Rightarrow x=9,8\div10\)
\(\Rightarrow x=0,98\)
CÁCH LÀM NHƯ SAU :
(7/28 + 1/28) + 1/70 + 1/130 + 1/x.(x+3)
8/28 + 1/70 +1/130 +1/x.(x+3)
2/7+1/70+1/130+1/x.(x+3)
(20/70 +1/70)+1/130+1/x.(x+3)
3/10+1/130+1/x.(x+3)
39/130+1/130+1/x.(x+3)
4/13+1/x.(x+3)
Đến đây bn tự làm hộ mình vớ. chúc hok tốt k cho mình nhé
\(\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+\frac{1}{130}+\frac{1}{x\left(x+3\right)}\)
\(=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+\frac{1}{x\left(x+3\right)}\)
\(=\frac{1}{3}\left(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{x}-\frac{1}{x+3}\right)\)
\(=\frac{1}{3}\left(\frac{1}{1}-\frac{1}{13}+\frac{1}{x}-\frac{1}{x+3}\right)\)
\(=\frac{1}{3}\left(\frac{12}{13}+\frac{1}{x}-\frac{1}{x+3}\right)\)
\(=\frac{1}{3}.\frac{12}{13}+\frac{1}{3}.\frac{1}{x}-\frac{1}{3}.\frac{1}{x+3}\)
\(=\frac{4}{13}+\frac{1}{3x}-\frac{1}{3x+3}\)
\(=\frac{4}{13}+\frac{1}{3x}-\frac{1}{3x+3}\)
\(=\frac{4}{13}+\frac{1}{3x}=\frac{1}{3x+3}\)
\(=\frac{4}{13}+\frac{1}{3x}=\frac{1}{3x+3}\)
\(=\frac{4}{13}+\frac{1}{3x}=\frac{1}{3}.\frac{1}{x+3}\)
\(=\frac{4}{13}=\frac{1}{3}.\frac{1}{x+3}-\frac{1}{3x}\)
\(=\frac{4}{13}=\frac{1}{3}.\frac{1}{x+3}-\frac{1}{3}.\frac{1}{x}\)
\(=\frac{4}{13}=\frac{1}{3}\left(\frac{1}{x+3}-\frac{1}{x}\right)\)
\(=\frac{4}{13}:\frac{1}{3}=\frac{1}{x+1}-\frac{1}{x}\)
\(=\frac{12}{13}=\frac{1}{x+1}-\frac{1}{x}\)
\(=\frac{12}{13}=\frac{x-\left(x+1\right)}{\left(x+1\right)x}\)
\(=\frac{12}{13}=-\frac{1}{x^2+x}\)
\(\Leftrightarrow=12\left(x^2+x\right)=13.\left(-1\right)\)
\(=12\left(x^2+x\right)=-13\)
\(=x^2+x=-\frac{13}{12}\)
\(=x\left(x+1\right)=-\frac{13}{12}\)
.... Chiụ
trả lời
tui trả lời rui mà
chúc bà học tốt
nhớ k tui nha
cám ơn các bn
=36x(28+82)+64x(69+41)
=36x110+64x110
=110x(36+64)
110x100
=11000
36x28+36x82+64x69+64x41
=36x(28+82)+64x(69+41)
=36x110+64x110
=110x(36+64)
=110x100
=11 000
28+62.a.(a.1-a:1)+28.8+28=28.10+62.a.(a-a)=280+62.a.0=280
Đáp án:280
~Hok tốt~