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a) x - 28 .65 = 50.19 => x = 50.19 + 28.65 => x = 78.84
b) x- 5.88 = 33.7 + 61.5 => x - 5.88 = 95.2 => x = 95.2 + 5.88 => x = 101.08
c) x - 108.34 - 45.99 = 168.04 => x - 108.34 = 168.04 + 45.99 => x = 214.03 + 108.34 => x = 322.37
d) ( x + 12.39 ) / 0.76 = 205.8 => x + 12.39 = 205.8 * 0.76 => x = 156.408 - 12.39 => x = 168.798
a, ta lập được
a lấy 3 lần,b lấy 2 lần,c lấy 1 lần nên 3 x 2 x 1 = 6 số có 3 chữ số khác nhau
b,số b là
18 : 3 = 6
số c là
6 - 1 = 5
số a là
6 + 1 = 7
1)
\(\left(a\right)37+397+3997+39997\)
\(=40-3+400-3+4000-3+40000-3\)
\(=\left(40+400+4000+40000\right)-\left(3+3+3+3\right)\)
\(=44440-12=44428\)
\(\left(b\right)298+2998+29998+299998\)
\(=300-2+3000-2+30000-2+300000-2\)
\(=\left(300+3000+30000+300000\right)-\left(2+2+2+2\right)\)
\(=333300-8=333296\)
\(\left(c\right)9+99+999+9999+99999\)
\(=10-1+100-1+1000-1+10000-1+100000-1\)
\(=\left(10+100+1000+10000+100000\right)-\left(1+1+1+1+1\right)\)
\(=111110-5=111105\)
2)
\(\left(a\right)\left(2+4+6+...+2002+2004+2006\right)-\left(1+3+5+...+2001+2003+2005\right)\)
\(=\left(2-1\right)+\left(4-3\right)+\left(6-5\right)+...+\left(2002-2001\right)+\left(2004-2003\right)+\left(2006-2005\right)\)
\(=1+1+1+...+1+1+1\)( 1003 số 1 )
\(=1003\)
\(\left(b\right)88-87+86-85+84-83+...+6-5+4-3+2-1\)
\(=\left(88-87\right)+\left(86-85\right)+\left(84-83\right)+...+\left(6-5\right)+\left(4-3\right)+\left(2-1\right)\)
\(=1+1+1+...+1+1+1\)( 44 số 1 )
\(=44\)
\(\left(c\right)100-98+96-94+92-90+...+12-10+8-6+4-2\)
\(=\left(100-98\right)+\left(96-94\right)+\left(92-90\right)+...+\left(12-10\right)+\left(8-6\right)+\left(4-2\right)\)
\(=2+2+2+...+2+2+2\) ( 25 số 2 )
\(=50\)
3)
\(\left(a\right)360-357+354-351+348-345+...+312-309+306-303+300-297\)
\(=\left(360-357\right)+\left(354-351\right)+\left(348-345\right)+...+\left(312-309\right)+\left(306-303\right)+\)\(\left(300-297\right)\)
\(=3+3+3+3+3+3+3+3+3+3+3=33\)
\(\left(b\right)2006-1-2-3-4-...-47-48-49-50\)
\(=2006-\left(1+2+3+4+...+47+48+49+50\right)\)
\(=2006-\frac{\left(50+1\right)\left[\left(50-1\right)+1\right]}{2}\)
\(=2006-1275=731\)
\(\left(c\right)280-276+272-268+264-260+...+216-212+208-204+200-196\)
\(=\left(280-276\right)+\left(272-268\right)+\left(264-260\right)+...+\left(216-212\right)+\left(208-204\right)+\)\(\left(200-196\right)\)
\(=4+4+4+4+4+4+4+4+4+4+4=44\)
\(\frac{9}{9}=1\)
\(\frac{4}{5}=0,8\)
Do đó: \(\frac{9}{9}>\frac{4}{5}\)
Nên: \(x=9\)
\(\frac{9}{9}\)= 1
\(\frac{4}{5}\)= 0,8
nên \(\frac{9}{9}\)> \(\frac{4}{5}\)
Vậy x = 9
Điền dấu <;>;= :
a)11/25..<.......12/25
b)9/5......>.....8/5
c)36/45....=........4/5
d)5/8......<.......3/4
A,
0,7.0,25.2,4=0,42
B,
6,33+9,48+3,67+2,52
=(6,33+3,67)+(9,48+2,52)
=10+12
=22
C,
2,5.12,5.0,8.4
=100
D,
20,09-(3,49+6,51)
=20,09-10
=10,09