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Ta có:
\(\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{100}\right)\)
\(=\left(\frac{3}{3}-\frac{1}{3}\right)\left(\frac{4}{4}-\frac{1}{4}\right)\left(\frac{5}{5}-\frac{1}{5}\right)...\left(\frac{100}{100}-\frac{1}{100}\right)\)
\(=\left(\frac{3-1}{3}\right)\left(\frac{4-1}{4}\right)\left(\frac{5-1}{5}\right)...\left(\frac{100-1}{100}\right)\)
\(=\frac{2}{3}.\frac{3}{4}.\frac{4}{5}...\frac{99}{100}\)
\(=\frac{2.3.4...99}{3.4.5...100}=\frac{2}{100}=\frac{1}{50}\)
Vậy \(\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{100}\right)=\frac{1}{50}\)
\(\left(1-\frac{1}{99}\right)\left(1-\frac{1}{100}\right).....\left(1-\frac{1}{2005}\right)\)
\(=\frac{98}{99}.\frac{99}{100}.....\frac{2004}{2005}=\frac{98}{2005}\)
1. a) 76 x 34 + 86 x 34
= 34 x ( 76 + 86 )
= 34 x 162
= 5508
b) 1 x 3 + 1 x 4 + 1 x 7 + 1
= 1 x 3 + 1 x 4 + 1 x 7 + 1 x 1
= 1 x ( 3 + 4 + 7 + 1 )
= 1 x 15
= 15
(1-1/99)x(1-1/100)x(1-1/101)x....x(1-1/2016)
=98/99x99/100x100/101x.....x2015/2016
=98/2016
=7/144
nhớ **** cho mình nha
Gọi biểu thức trên là A, ta có :
A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100
A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
A x 3 = 99x100x101
A = 99x100x101 : 3
A = 333300
(1+1/105)x(1+1/106)x(1+1/107)x(1+1/108)+(1+1/109)
=109/105+110/109
=23431/11445
(125 x 4 - 1000 : 2) x ( 1 x2 x 3 x... x 99 x 100)
=(500 - 500 ) x ( 1 x2 x 3 x... x 99 x 100)
=0 x ( 1 x2 x 3 x... x 99 x 100)
=0
( 125 x 4 - 1000 : 2 ) x ( 1 x 2 x 3 x ... x 99 x 100 )
Đặt A = 125 x 4 - 1000 : 2
B = 1 x 2 x 3 x ... x 99 x 100
A = 125 x 4 - 1000 : 2
A = 500 - 500
A = 0
Thay vào , ta có :
0 x ( 1 x 2 x 3 x ... x 99 x 100 )
= 0