Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
M = \(2.\frac{1}{547}.\frac{3}{211}-\frac{546}{547}.\frac{1}{211}-\frac{1}{247.211}\)
M = \(\frac{6}{547.211}-\frac{546}{547.211}-\frac{4}{547.211}\)
M = \(\frac{-544}{547.211}\)
\(M=2.\frac{1}{547}.\frac{3}{211}-\frac{546}{547}.\frac{1}{211}-\frac{4}{547.211}\)
\(M=\left(2.\frac{1}{547}.\frac{3}{211}\right)-\left(\frac{546}{547}.\frac{1}{211}\right)-\left(\frac{4}{547.211}\right)\)
\(M=\frac{6}{547.211}-\frac{546}{547.211}-\frac{4}{547.211}\)
\(M=\frac{6}{115417}-\frac{546}{115417}-\frac{4}{115417}\)
\(M=\frac{-540}{115417}-\frac{4}{115417}\)
\(M=\frac{-544}{115417}\)
gọi 1/547=a, 1/211=b ta đc:
\(2a.3b-546a.b-4ab< =>6ab-546ab-4ab=-544ab=\dfrac{-544}{547.211}\)
a) \(\frac{278}{37}\) và \(\frac{287}{46}\)
Vì \(37< 46\) nên \(\frac{278}{37}>\frac{287}{46}\)
b) \(\frac{547}{216}\) và \(\frac{546}{215}\)
Ta có:
\(\frac{547}{216}-2=\frac{115}{216}\)
\(\frac{546}{215}-2=\frac{116}{215}\)
Vì \(\frac{115}{216}< \frac{116}{215}\) nên \(\frac{547}{216}< \frac{546}{215}\)
a) \(\frac{278}{37}=7+\frac{19}{37}\) \(\frac{287}{46}=7-\frac{35}{46}\)
\(\frac{278}{37}>7>\frac{287}{46}\Rightarrow\frac{278}{37}>\frac{287}{46}\)
b) Ta có: \(\frac{547}{216}=1+\frac{331}{216}\)
\(\frac{546}{215}=1+\frac{331}{215}\)
mà \(\frac{331}{216}< \frac{331}{215}\)
=> \(\frac{547}{216}< \frac{546}{215}\)
\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-7}{20}\)
\(x=\frac{1}{4}:\frac{-7}{20}\)
\(x=\frac{-5}{7}\)
\(2x\left(x-\frac{1}{7}\right)=0\)
\(=>x=0\) hoặc \(x-\frac{1}{7}=0\)
\(x=0+\frac{1}{7}\)
\(x=\frac{1}{7}\)
Vậy \(x\in\left\{0;\frac{1}{7}\right\}\)
Mình làm câu b thôi nha
\(\frac{3}{4}\) + \(\frac{1}{4}\) : x = \(\frac{2}{5}\)
\(1\) : x = \(\frac{2}{5}\)
x = \(1\) * \(\frac{2}{5}\)
x = \(\frac{5}{2}\)
Answer : \(\frac{5}{2}\)
\(-\frac{544}{115417}\)
\(-\frac{544}{115417}\)
#Hok_tốt