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1. x( x - 3 ) + y( y - 3 ) + 2xy - 35
= x2 - 3x + y2 - 3y + 2xy - 35
= ( x2 + 2xy + y2 ) - ( 3x + 3y ) - 35
= ( x + y )2 - 3( x + y ) - 35
= 52 - 3.5 - 35
= 25 - 15 - 35 = -25
2. 4x2 + y2 + 8x - 4xy - 4y + 100
= ( 4x2 - 4xy + y2 + 8x - 4y + 4 ) + 96
= [ ( 4x2 - 4xy + y2 ) + ( 8x - 4y ) + 4 ] + 96
= [ ( 2x - y )2 + 2.( 2x - y ).2 + 22 ] + 96
= ( 2x - y + 2 )2 + 96
= ( 4 + 2 )2 + 96
= 62 + 96 = 36 + 96 = 132
a) \(M=\left(x+y\right)^3+2x^2+4xy+2y^2\)
\(=7^3+2\left(x^2+2xy+y^2\right)\)
\(=343+2\left(x+y\right)^2\)
\(=343+2.7^2\)
\(=343+98=441\)
b) \(N=\left(x-y\right)^3-x^2+2xy-y^2\)
\(=\left(-5\right)^3-\left(x-y\right)^2\)
\(=-125-\left(-5\right)^2\)
\(=-125-25=-150\)
Viết lại :
a) \(M=\left(x+y\right)^3+2\left(x+y\right)^2\)
b) \(N=\left(x-y\right)^3-\left(x-y\right)^2\)
a) M=(x+y)3+2x2+4xy+2y2
M=73+(2x+2y)2=4(x+y)2=73+4.72=343+196=539
b)N=(x-y)3-x2+2xy-y2
N=-53-(x2-2xy+y2)=-125-(x-y)2=-125-(-5)2=-150
\(A=x^3+y^3-2x^2-2y^2+3xy\left(x+y\right)-4xy+3\left(x+y\right)+10\)
\(A=\left(x^3+y^3\right)-2\left(x^2+y^2\right)+3xy\left(x+y\right)-4xy+3\left(x+y\right)+10\)
\(A=\left(x+y\right)^3-3xy\left(x+y\right)-2\left(\left(x+y\right)^2-2xy\right)+3xy\left(x+y\right)-4xy+3\left(x+y\right)+10\)
\(A=\left(x+y\right)^3-3xy\left(x+y\right)-2\left(x+y\right)^2+4xy+3xy\left(x+y\right)-4xy+3\left(x+y\right)+10\)
\(A=\left(5\right)^3-3xy\left(5\right)-2\left(5\right)^2+4xy+3xy\left(5\right)-4xy+3\left(5\right)+10\)
\(A=125-15xy-50+4xy+15xy-4xy+15+10\)
\(A=100\)
2) b)
Do \(a+b+c=9\Rightarrow\left(a+b+c\right)^2=81\)
\(\Rightarrow a^2+b^2+c^2+2\left(ab+bc+ac\right)=81\)
\(\Rightarrow2\left(ab+bc+ac\right)=81-141=-60\)
\(ab+bc+ac=-60:2=-30\)
a, B=x^3 + 3xy +y^3 = x^3 +3xy(x+y)+y^3 (vì x+y=1)
= (x+y)^3
= 1^3 =1
b, (a+b+c)^2 =a^2 +b^2 +c^2 +2ab +2bc +2ac
9^2 = 141 +2(ab+bc+ac)
-60 = 2(ab+bc+ac)
ab+ac+bc=-30
Vậy M=-30
c, N =(x+y)^3 -3(x+y)(x^2+y^2) +2(x^3+y^3)
= x^3 + 3x^2 .y + 3xy^2 + -3(x^3+xy^2 +x^2 .y+y^3)+ 2x^3 +2y^3
= x^3 +3x^2 .y + 3xy^2 - 3x^3 -3xy^2 -3x^2 .y -3y^3 +2x^3 +2y^3
= 0
Vậy N=0 .Chúc bạn học tốt.