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1 / 7/4 - y . 5/6 = 1/2 + 1/3
7/4 - 5/6y = 5/6
5/6y = 7/4 - 5/6
5/6y = 11/12
y = 11/12 : 5/6
y = 11/10
2 . 136 là số chia 9 dư 1
=> y = 136 - 1 = 135
3 . Dựa theo quy luật của dãy thì số tiếp theo là :
1/16 : 2 = 1/32
1: y = \(\frac{11}{10}\)
2: Y = 135
3: Số hạng tiếp theo của dãy: \(\frac{1}{32}\)
7/4-y x 5/6 = 1/2+1/3
7/4-y x 5/6=5/6
y x 5/6=7/4-5/6
y x 5/6=11/12
y=11/12 : 5/6
y=11/10
\(\frac{7}{4}-y\times\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{4}-y\times\frac{5}{6}=\frac{5}{6}\)
\(\frac{7}{4}-y=\frac{5}{6}\div\frac{5}{6}\)
\(\frac{7}{4}-y=1\)
\(y=1+\frac{7}{4}\)
\(y=\frac{11}{4}\)
a) \(\frac{7}{10}-y\cdot\frac{3}{4}=\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{1}{2}\)
\(y=\frac{1}{2}:\frac{3}{4}\)
\(y=\frac{1}{2}\cdot\frac{4}{3}\)
\(y=\frac{2}{3}\)
b) \(\frac{5}{6}:\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}:\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}\cdot\frac{4}{3}\)
\(y+\frac{7}{9}=\frac{10}{9}\)
\(y=\frac{10}{9}-\frac{7}{9}\)
\(y=\frac{3}{9}=\frac{1}{3}\)
**** !
a, \(\frac{7}{10}-y\times\frac{3}{4}=\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow y=\frac{1}{2}\div\frac{3}{4}\)
\(\Rightarrow y=\frac{1}{3}\)
b, \(\frac{5}{6}\div\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{5}{6}\div\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{10}{9}\)
\(\Rightarrow y=\frac{10}{9}-\frac{7}{9}\)
\(\Rightarrow y=\frac{1}{3}\)
7/4-x*5/6=1/2+1/3
7/4-x*5/6=5/6
X=5/6:5/6
X=7/4-1
X=3/4
Chúc bạn HK tốt
a) 7/10 - y × 3/4 = 1/5
y × 3/4 = 7/10 - 1/5
y × 3/4 = 1/2
y = 1/2 : 3/4
y = 2/3. Vậy y = 2/3
b) 5/6 : ( y + 7/9 ) = 3/4
y + 7/9 = 5/6 : 3/4
y + 7/9 = 10/9
y. = 10/9 - 7/9
y = 1/3. Vậy y = 1/3
\(\frac{7}{10}\)- y * \(\frac{3}{4}\)= \(\frac{1}{5}\)
y * \(\frac{3}{4}\)= \(\frac{7}{10}\)- \(\frac{1}{5}\)
y * \(\frac{3}{4}\)= \(\frac{1}{2}\)
y = \(\frac{1}{2}\): \(\frac{3}{4}\)
y = \(\frac{2}{3}\)
Vậy y = \(\frac{2}{3}\)
\(\frac{5}{6}\): ( y + \(\frac{7}{9}\)) = \(\frac{3}{4}\)
y + \(\frac{7}{9}\) = \(\frac{5}{6}\): \(\frac{3}{4}\)
y + \(\frac{7}{9}\) = \(\frac{10}{9}\)
y = \(\frac{10}{9}\)- \(\frac{7}{9}\)
y = \(\frac{3}{9}\)
Vậy y = \(\frac{3}{9}\)
a, \(\frac{2}{5}\)+ y = 1
y = 1 - \(\frac{2}{5}\)
y = \(\frac{3}{5}\)
b, \(\frac{6}{8}\)- y = \(\frac{3}{5}\)
y = \(\frac{6}{8}\)- \(\frac{3}{5}\)
y = \(\frac{3}{20}\)
c, y : 6 = \(\frac{7}{4}\)
y = \(\frac{7}{4}\)x 6
y = \(\frac{21}{2}\)
d, y - \(\frac{1}{3}\)= 5 x \(\frac{2}{3}\)
y - \(\frac{1}{3}\)= \(\frac{10}{3}\)
y = \(\frac{10}{3}\)+ \(\frac{1}{3}\)
y = \(\frac{11}{3}\)
a,2/5 + y = 1
y = 1 - 2/5
y = 3/5
b, 6/8 - y = 3/5
y = 6/8 - 3/5
y = 3/10
c, y / 6 = 7/4
y = 7/4 * 6
y = 15/2
d, y - 1/3 = 5 * 2/3
y - 1/3 = 10/3
y = 10/3 + 1/3
y = 11/3