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Hoàng Thị Thanh Trúc
a,
\(\frac{x}{7}=\frac{6}{21}\Rightarrow x=\frac{6.7}{21}=2\)
b,
\(\frac{-5}{y}=\frac{20}{28}\Rightarrow y=\frac{\left(-5\right).28}{20}=-7\)
\(\frac{x}{7}=\frac{6}{21}\)
\(\Rightarrow x=\frac{7.6}{21}\)
\(\Rightarrow x=2\)
\(-\frac{5}{y}=\frac{20}{28}\)
\(\Rightarrow y=\frac{-5.28}{20}\)
\(\Rightarrow y=-7\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\Rightarrow\frac{x}{10}=\frac{y}{6}=\frac{z}{21}=\frac{5x}{50}=\frac{y}{6}=\frac{2z}{42}=\frac{5x+y-2z}{50+6-42}=\frac{28}{14}=2\)
\(\Rightarrow\begin{cases}\frac{x}{10}=2\\\frac{y}{6}=2\\\frac{z}{21}=2\end{cases}\)\(\Rightarrow\begin{cases}x=20\\y=12\\z=42\end{cases}\)
Vậy x=20;y=12;z=42
a) y = 28.(-9):21 = -12
Thế y vào ta có: x = 6.28:(-12) = -14
Vậy x = -14, y = -12
b) Ta có: 5/6+(-2/3).1/5 = 7/10
x = 7.30:10 = 21
Vậy x = 21
dễ ợt
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}.\)
\(\Rightarrow x.\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)=\frac{8}{9}\)
\(\Rightarrow x.\frac{23}{52}=\frac{8}{9}\)
\(\Rightarrow x=\frac{426}{207}\)
Study well
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}\)
<=> x\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{x}{39}\right)=\frac{8}{9}\)
<=> x = \(\frac{8}{9}:\frac{23}{52}\)
<=> x = \(\frac{416}{207}\)
\(\frac{3}{x-5}=-\frac{4}{x+2}\)
\(\Leftrightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
\(\frac{x}{-2}=-\frac{8}{x}\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x=\pm4\)
\(-\frac{2}{x}=\frac{y}{3}\)
\(\Leftrightarrow xy=-6\)
\(\Leftrightarrow x;y\inƯ\left(-6\right)=\left\{\pm1;\pm2;\pm3;\pm6\right\}\)
Xét bảng
x | 1 | -1 | 2 | -2 | 3 | -3 | 6 | -1 |
y | -6 | 6 | -3 | 3 | -2 | 2 | -1 | 6 |
Vậy.................
\(\frac{2x-9}{240}=\frac{39}{80}\)
\(\Leftrightarrow2x-9=\frac{240.39}{80}\)
\(\Leftrightarrow2x-9=117\)
\(\Leftrightarrow2x=126\)
\(\Leftrightarrow x=63\)