Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x+11\right)^3=32.25+200.\)
\(\left(7x+11\right)^3=800+200.\)
\(\left(7x-11\right)^3=1000.\)
\(\left(7x-11\right)^3=10^3.\)
\(\Rightarrow7x-11=10.\)
\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)
Vậy.....
\(b,3^x+25=26.2^2+2.3^0.\)
\(3^x+25=26.4+2.\)
\(3^x+25=104+2.\)
\(3^x+25=106.\)
\(3^x=106-25.\)
\(3^x=81.\)
\(3^x=3^4\Rightarrow x=4\in Z.\)
Vậy.....
\(c,2^x+3.2=64.\)(có vấn đề).
\(d,5^{x+1}+5^x=750.\)
\(5^x.5^1+5^x+1=750.\)
\(5^x\left(5^1+1\right)=750.\)
\(5^x\left(5+1\right)=750.\)
\(5^x.6=750.\)
\(5^x=750:6.\)
\(5^x=125.\)
\(5^x=5^3\Rightarrow x=3\in Z.\)
Vậy.....
\(e,x^{15}=x.\)
\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)
\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)
\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)
\(6-x=0\Rightarrow x=6\in Z.\)
\(x-4=0\Rightarrow x=4\in Z.\)
Vậy.....
\(\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x-11\right)^3=800+200\)
\(\left(7x-11\right)^3=1000\)
\(\left(7x-11\right)^3=10^3\)
\(\Leftrightarrow7x-11=10\)
\(\Leftrightarrow7x=10+11\)
\(\Leftrightarrow7x=21\)
\(\Leftrightarrow x=3\)
Vậy ...........
(7x -11)3 - 200 = 25. 52
(7x - 11)3 - 200 = 32 . 25
(7x - 11)3 - 200 = 800
(7x - 11)3 = 800 + 200
(7x - 11)3 = 1000
(7x -11)3 = 103
7x - 11 = 10
7x = 10 + 11
7x = 21
x = 21: 7
x = 3
Vậy x=3
(7x-11)3 = 23 x 52 +200
(7x-11)3 = 8 x 25 +200
(7x-11)3 = 200 +200
(7x-11)3 = 400
(7x-11)3 = đề sai
(7x-11)3 = 23 x 52 +200
(7x-11)3 = 8 x 25 +200
(7x-11)3 = 200 +200
(7x-11)3 = 400
(7x-11)3 = đề sai
=> không tính được
\(6^{x-2}\) :12 =3
\(6^{x-2}\) = 3.12
\(6^{x-2}\) = 36
\(6^{x-2}\) = \(6^2\)
⇒ x - 2 =2
x = 2+ 2
x = 4
Vậy x =4
3 + \(2^{x-1}\) = 24 - [\(4^2\) - (\(2^2\) -1)]
3 + \(2^{x-1}\) = 24 - [16 - (4-1)]
3 + \(2^{x-1}\) = 24 - (16 - 3)
3 + \(2^{x-1}\) = 24 - 13
3 + \(2^{x-1}\) = 11
\(2^{x-1}\) = 11-3
\(2^{x-1}\) = 8
\(2^{x-1}\) = \(2^3\)
⇒ x - 1 = 3
x = 3 + 1
x = 4
Vậy x = 4
\(\left(7x-11\right)^3\) = \(2^5.5^2+200\)
\(\left(7x-11\right)^3\)\(\left(7x-11\right)^3\)
( 7x - 11 )3 = 25 . 52 + 200
\(\Rightarrow\)( 7x - 11 )3 = 32 . 25 + 200
\(\Rightarrow\)( 7x - 11 )3 = 800 + 200
\(\Rightarrow\)( 7x - 11 )3 = 1000
\(\Rightarrow\)( 7x - 11 )3 = 103
\(\Rightarrow\)7x - 11 = 10
\(\Rightarrow\)7x = 10 + 11 = 21
\(\Rightarrow\)x = 21 : 7
\(\Rightarrow\)x = 3
( 7x - 11 )3 = 25 . 52 + 200
( 7x - 11 )3 = 32 . 25 + 200
( 7x - 11 )3 = 800 + 200
( 7x - 11 )3 = 1000
( 7x - 11 )3 = 103
7x - 11 = 10
7x = 10 + 11
7x = 21
x = 21 : 7
x = 3
(7x-11)3=25.22+200
(7x-11)3=25+2+200
(7x-11)3=27+200
(7x-11)3=128+200
(7x-11)3=328
xong hết bt