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a.
(-2)4.17.(-3)0.(-5)6.(-12n)
=16.17.1.15625.-1
=(16.15625).[1.(-1)].17
=250000.(-1).17
=4250000
b.3(2x2-7)=33
2x2-7 =33:3
2x2-7 =11
2x2 =11+7
2x2 =18
x2 =18:2
x2 =9
x2 =\(\left(\pm3^2\right)\)
\(\Rightarrow\) TH1: x2 =32 TH2: x2 =(-3)2
\(\Rightarrow\) x =3 \(\Rightarrow\)x =-3
Vậy x\(\in\left\{3;-3\right\}\)
\(\left(x-1\right)^3=125\)
\(\left(x-1\right)^3=5^3\)
\(=>x-1=5\)
\(x=6\)
Tương tự các câu cn lại
a) ( x - 1 ) 3 = 125
( x - 1 ) 3 = 53
x - 1 = 5
x = 5 + 1
x = 6
tích nha
\(A=3+3^2+3^3+3^4+...+3^{100}\)
\(3A=3^2+3^3+...+3^{101}\)
\(3A-A=\left[3^2+3^3+...+3^{101}\right]-\left[3+3^2+3^3+...+3^{100}\right]\)
\(2A=3^{101}-3\)
\(A=\frac{3^{101}-3}{2}\)
Ta lại có : \(2A+3=3^x\)
=> \(2\cdot\frac{3^{101}-3}{2}+3=3^x\)
=> \(3^{101}-3+3=3^x\)
=> 3101 = 3x
=> x = 101
Vậy x = 101
\(3A=3^2+3^3+...+3^{101}\)
\(\Rightarrow2A=3^{101}-3\)
\(\Rightarrow2A+3=3^{101}=3^x\)
\(\Rightarrow x=101\)
c) 2x+(15-(7-4)2)=24.3
2x+(15-32)=16.3
2x+(15-9)=48
2x+6=48
2x=48-6
2x=42
x=42:2
x=21
Vậy...
a, 17+(-x)=-16-(-34)
<=> 17+(-x)= - 50
=> -x= - 33
=> x= 33
b, x-40=9.(-5)+9
<=> x-40= -36
=> x= 4
c, 2x + [ 15 - ( 7 - 4 ) 2 ] = 24 . 3
<=> 2x+ [ 15- 32 ] = 48
<=> 2x+4=48
=>2x=44
=>x=22
d, 1125-10x-3 = 152 - 102
=> 1125 - 10x-3 = 125
=> 10x-3 = 1000
=> 10x-3= 103
=> x-3=3
=>x=6
\(a)3-\left(17-x\right)=-24+12\)
\(\Leftrightarrow3-17+x=-12\)
\(\Leftrightarrow-14+x=-12\)
\(\Leftrightarrow x=-12+14=2\)
a) 3 - (17 - x) = -24 + 12
=> 3 - 17 + x = -12
=> -14 + x = -12
=> x = -12 + 14
=> x = 2
b) -5 + (16 - x) = 22.3 - 52
=> -5 + 16 - x = 12 - 25
=> 11 - x = -13
=> x = 11 + 13
=> x = 24
c) -26 - (x - 7) = 34 - 92
=> -26 - x + 7 = 81 - 81
=> -19 - x = 0
=> x = -19 - 0
=> x = -19
d) -36 - (4 - x) = 37 + (-5)
=> -36 - 4 + x = 32
=> -40 + x = 32
=> x = 32 + 40
=> x = 72
(7x-11)3=25.52+200
=> (7x-11)3=800+200
=> (7x-11)3=1000
=> (7x-11)3=103
=> 7x - 11 = 10
=> 7x = 21
=> x = 3
(2x-15)5=(2x-15)3
=> (2x-15)5 - (2x-15)3 = 0
=> (2x-15)3 . [ (2x-15)2 - 1 ] = 0
=> \(\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}\Rightarrow\orbr{\begin{cases}2x-15=0\\2x-15=1\end{cases}\Rightarrow}\orbr{\begin{cases}2x=15\\2x=16\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{15}{2}\\x=8\end{cases}}}\)
Mà x thuộc N
=> x = 8
(3x-5)10=(3x-5)9
=> (3x-5)10 - (3x-5)9 = 0
=> (3x-5)9 .[ (3x-5) - 1 ] = 0
=> \(\orbr{\begin{cases}\left(3x-5\right)^9=0\\\left(3x-5\right)-1=0\end{cases}\Rightarrow\orbr{\begin{cases}3x-5=0\\3x-5=1\end{cases}\Rightarrow}\orbr{\begin{cases}3x=5\\3x=6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=2\end{cases}}}}\)
Mà x thuộc N
=> x = 2
a)(7x-11)^3=1000
(7x-11)^3=10^3
7x-11 =10
7x =10+11=21
x =21:7=3
a) \(2^2.2^4.x=16^2\)
\(2^6x=\left(2^4\right)^2\)
\(2^6.x=2^8\)
\(x=2^8:2^6\)
\(x=2^2\)
\(x=4\)
vay \(x=4\)
b) \(5^{2x+1}=125\)
\(5^{2x+1}=5^3\)
\(\Rightarrow2x+1=3\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
vay \(x=1\)
c) \(\left(2x-1\right)^3=64\)
\(\left(2x-1\right)^3=4^3\)
\(\Rightarrow2x-1=4\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\frac{5}{2}\)
vay \(x=\frac{5}{2}\)
\(5x+2x=6^2-5^0\Leftrightarrow5x+2x=6^2-1\)
\(\Leftrightarrow5x-2x=36-1\Leftrightarrow5x-2x=35\Leftrightarrow x\left(5+2\right)=35\)
\(\Leftrightarrow7x=35\Leftrightarrow x=35:7\Leftrightarrow x=5\)
\(5x+x=150:2+3\Leftrightarrow5x+x=75+3\)
\(\Leftrightarrow5x+x=78\Leftrightarrow x\left(5+1\right)=78\Leftrightarrow x6=78\)
\(\Leftrightarrow x=78:6\Leftrightarrow x=13\)
a) 5x + 2x = 62 - 50
7x = 35 => x = 5
b) 5x + x = 150 : 2 + 3
6x = 78 => x = 13
c) 6x + x = 511 : 59 + 31
7x = 28 => x = 4
d) 5x + 3x = 36 : 33 x 4 + 12
8x = 120 => x = 15
e) 4x + 2x = 68 - 219 : 216
6x = 60 => x = 10
f) 5x + x = 39 - 311 : 39
6x = 30 => x = 5
g) 7x - x = 521 : 519 + 3 x 22 - 70
6x = 36 => x = 6
h) 7x - 2x = 617 : 615 + 44 : 11
5x = 40 => x = 8
\(a,\left(x-2\right)^2=4^2\)
\(\Rightarrow\hept{\begin{cases}x-2=4\\x-2=-4\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=6\\x=-2\end{cases}}\)
Bài 1:
a) \(\left(x-2\right)^2=16\)
\(\Rightarrow\left(x-2\right)^2=4^2\)
\(\Rightarrow x-2=4\)
\(\Rightarrow x=4+2=6\)
b) \(\left(2x-3\right)^2=9\)
\(\Rightarrow\left(2x-3\right)^2=3^2\)
\(\Rightarrow2x-3=3\)
\(\Rightarrow2x=3+3=6\)
\(\Rightarrow x=6:2=3\)
Bài 2 tương tự nhé em
P/s: Chỉ cần phân tích vế phải sao cho cùng số mũ với vế trái là được nhé!
Chúc em học tốt!
A, (2x+1)3=343
=> (2x+1)3=73
=> 2x + 1 = 7
=> 2x = 6
=> x = 3
B, 2x+2x+3=144
=> 2x+2x . 23 =144
=> 2x ( 1 + 23 ) =144
=> 2x ( 1 + 8 ) =144
=> 2x . 9 =144
=> 2 x = 16
=> 2 x = 2 4
=> x = 4
C, 3x+3x+2=2430
=> 3x+3x . 32 =2430
=> 3x . ( 1 + 32 ) =2430
=> 3x . ( 1 + 9 ) =2430
=> 3x . 10 =2430
=> 3x = 243
=> 3x = 3 5
=> x = 5