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a)Câu a sai đề
b)x=4
k mik nha
Học tốt
viết lại đề câu a nha
a, 2x . 4 = 128
2x = 128 : 4
2x = 32
2x = 25
=> x = 5
b, x15 = x1
=> x15 - x = 0
x . ( x14 - 1 ) = 0
=> x = 0 hoặc x14 - 1 = 0
=> x = 0 hoặc x = 1
c, (2x + 1)3 = 125
( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 5 - 1
=> 2x = 4
=> x = 4 : 2
=> x = 2
d, (x – 5)4 = (x - 5)6
=> ( x - 5 )6 - ( x - 5 )4 = 0
=> ( x - 5 )4 . [ ( x - 5 )2 - 1 ] = 0
=> \(\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=6\end{cases}}}\)
e, x10 = x
x10 - x = 0
x . ( x9 - 1 ) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x^9-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)
f, (2x -15)5 = (2x -15)3
( 2x - 15 )5 - ( 2x - 15 )3 = 0
( 2x - 15 )3 . [ ( 2x - 15 )2 - 1 ] = 0
\(\Rightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}\Rightarrow\orbr{\begin{cases}2x-15=0\\2x-15=1\end{cases}\Rightarrow}\orbr{\begin{cases}x\text{ không tồn tại}\\x=8\end{cases}}}\)
\(\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(2x+1=5\)
\(2x=5-1\)
2x=4
x=4/2
x=2
\(\left(4x-1\right)^2=25\cdot9\)
\(\left(4x-1\right)^2=225\)
\(\left(4x-1\right)^2=15^2\)
\(4x-1=15\)
4x=15+1
4x=16
x=16/4
x=4
\(\left(x-1\right)^3=125\)
\(\left(x-1\right)^3=5^3\)
\(x-1=5\)
\(x=5+1\)
\(\Rightarrow x=6\)
\(\left(x-1\right)^3=125\)
\(\left(x-1\right)^3=5^3\)
\(=>x-1=5\)
\(x=6\)
Tương tự các câu cn lại
a) ( x - 1 ) 3 = 125
( x - 1 ) 3 = 53
x - 1 = 5
x = 5 + 1
x = 6
tích nha
a) 5^x=125
=> 5^x=5^2
=>x=2
b) 3^2*x=81
=>3^2*x=9^2
=>3^2*x=(3^2)^2
=>x=2
câu c chưa hiểu chỗ 5^2x3 hay 5^2*3 vậy ?
a) \(5^x=125\)
\(5^x=5^3\)
\(\Rightarrow x=3\)
b)\(3^{2x}=81\)
\(3^{2x}=3^4\)
\(\Rightarrow2x=4\)
\(x=4:2\)
\(x=2\)
c)\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=5^2.3+5^2.2\)
\(5^{2x-3}=5^2.\left(3+2\right)\)
\(5^{2x-3}=5^3\)
\(\Rightarrow2x-3=3\)
\(2x=3+3\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
5x+1 = 125 = 53
x + 1 = 3 => x = 2
b) 3x-1 = 81 = 34
x - 1 = 4 => x= 5
c) (x - 6)2 = 9 = 32
x - 6 = 3 => x = 9
(2x - 7)2 = 169 = 132
2x - 7 = 13 => x = 10
d) x3 = 216 = 23.3
x3 = (2.3)3 = 63
Vậy x = 6
a) \(\left(4x+5\right):3-121:11=4\)
\(\Leftrightarrow\left(\dfrac{4x}{3}+\dfrac{5}{3}\right)-11=4\)
\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5}{3}-11=4\)
\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5}{3}-\dfrac{33}{3}=4\)
\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5-33}{3}=4\)
\(\Leftrightarrow\dfrac{4x}{3}-\dfrac{28}{3}=4\)
\(\Leftrightarrow\dfrac{4x}{3}=4+\dfrac{28}{3}\)
\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{12}{3}+\dfrac{28}{3}\)
\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{12+28}{3}\)
\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{40}{3}\)
\(\Leftrightarrow4x=\dfrac{40}{3}.3\)
\(\Leftrightarrow4x=40\)
\(\Leftrightarrow x=\dfrac{40}{4}=10\)
Vậy \(x=10\)
c) ( 2x + 1 )3 =125
=> (2x+1)3=53
=> 2x+1=5
=> 2x=4
=> x=2
vậy x=2
(2x + 1)3 = 125 = 53
=> 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4:2
x = 2
( 2x + 1 )3 = 125
53=125
=> 2x = 5-1
2x=4
x=4:2
x=2