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a)3x-1+5.3x-1=162
3x-1.1+5.3x-1=162
3x-1.(5+1)=162
3x-1.6=162
3x-1=162/6
3x-1=27
3x-1=33
Suy ra x-1=3
x=3+1=4
b)2x+3+2x=144
2x.8+2x=144
2x.8+2x.1=144
2x.(8+1)=144
2x.9=144
2x=144/9
2x=16
2x=24
Suy ra x=4
\(2^x.2^1=32:2=16\)
\(2^x.2^1=2^4\)
\(2^x=2^{4-1}=2^3\Rightarrow x=3\)
\(7^x.7^{12}=56-7=49\)
\(7^x.7^{12}=7^2\)
\(7^x=7^{2-12}=7^{-10}\Rightarrow x=-10\)
\(3^x.3^1=162:6=27\)
\(3^x.3^1=3^3\)
\(3^x=3^{3-1}=3^2\Rightarrow x=2\)
a) Ta có 3x - 1 + 5.3x - 1 = 162
<=> 6.3x - 1 = 162
<=> 3x - 1 = 27
<=> 3x - 1 = 33
<=> x - 1 = 3
<=> x = 4
Vậy x = 4 là giá trị cần tìm
b) 2x + 3 + 2x = 144
<=> 2x.23 + 2x = 144
<=> 2x.8 + 2x = 144
<=> 2x.9 = 144
<=> 2x = 16
<=> 2x = 24
<=> x = 4
Vậy x = 4 là giá trị cần tìm
a,5x + 5x + 2 = 650
=> 5x+5x.52=650
=> 5x.(1+25)=650
=> 5x=52
=> x=2
3x - 1 + 5 . 3x - 1 = 162
3x-1.(1+5)=162
=> 3x-1=27
=> 3x-1=33
=> x-1=3
=> x=4
5 x + 5 x + 2 = 650 3x - 1 + 5 . 3x - 1 = 162
5 x( 1 + 5 2 ) = 650 3x - 1 ( 5 + 1 ) = 162
5 x = 25 3x - 1 = 27
\(\Rightarrow\)x = 2 \(\Rightarrow\)x - 1 = 3
\(\Rightarrow\)x = 4
a, \(3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}.6=162\Rightarrow3^{x-1}=27=3^3\)
\(\Rightarrow x-1=3\Rightarrow x=4\)
b, \(2^{x+3}+2^x=144\)
\(\Rightarrow2^x.2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x=144:9=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
33 . 32x - 1 = 81
33 . 32x - 1 = 34
32x - 1 = 34 : 33 = 3
=> 2x - 1 = 1
2x = 2
x = 2 : 2 = 1
3^2.6.3^x+1=162
9.6.3^x+1=162
6.3^x+1=162:9
6.3^x+1=18
3^x+1=18:6
3^x+1=3
3^x+1=3^1
Suy ra x=0
vậy x=o thỏa mãn đề bài