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\(2^5.4=2^5.2^2=2^7\);\(5^4.25=5^4.5^2=5^6\); \(16^3.2^3=\left(2^4\right)^3.2^3=2^{12}.2^3=2^{15}\)
\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\); \(25^6:125^3=\left(5^2\right)^6:\left(5^3\right)^3=5^{12}:5^9=5^3\)
\(12^4.3^4=\left(2^2.3\right)^4.3^4=2^8.3^4.3^4=2^8.3^8=6^8\); \(9^6:3^2=\left(3^2\right)^6:3^2=3^{12}:3^2=3^{10}\)
\(2^3.2^4.2=2^8\)
a) \(\left(x-6\right)^3=\left(x-6\right)^2\Leftrightarrow\orbr{\begin{cases}x-6=1\Leftrightarrow x=7\\x-6=0\Leftrightarrow x=6\end{cases}}\)
b) \(\left(7.x-11\right)^3=2^5.5^2+200\)
\(\Leftrightarrow\left(7.x-11\right)^3=800+200\)
\(\Leftrightarrow\left(7.x-11\right)^3=1000\)
\(\Leftrightarrow\left(7.x-11\right)^3=10^3\)
\(\Leftrightarrow7x-11=10\Leftrightarrow7x=21\Leftrightarrow x=3\)
c) \(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)
\(\Leftrightarrow3+2^{x-1}=24-\left[4^2-3\right]\)
\(\Leftrightarrow3+2^{x-1}=24-13\)
\(\Leftrightarrow3+2^{x-1}=11\)
\(\Leftrightarrow2^{x-1}=8\Leftrightarrow2^{x-1}=2^3\Leftrightarrow x-1=3\Leftrightarrow x=4\)
a)\(3^x.3=243\Leftrightarrow3^x=81\Leftrightarrow3^x=3^4\Leftrightarrow x=4\)
b) \(2^x.16^2=1024\Leftrightarrow2^x.256=1024\Leftrightarrow2^x=4\Leftrightarrow2^x=2^2\Leftrightarrow x=2\)
c) \(64:4^x=16^8\Leftrightarrow4^x=67108864\Leftrightarrow4^x=4^{13}\Leftrightarrow x=13\)
d) \(2^x=16\Leftrightarrow2^x=2^4\Leftrightarrow x=4\)
125(28+72)-25(3^2.4+64)
=125.100-25(9.4+64)
=125.100-25.(36+64)
=125.100-25.100
=12500-2500
=10000
Bài 1 :
a/ \(a^3.a^9=a^{3+9}=a^{12}\)
b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)
c/ \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)
d/ \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)
e/ \(5^6:5^3+3^3.3^2\)
\(=5^3+3^5=125+243=368\)
i/ \(4.5^2-2.3^2\)
\(=2^2.5^2-2.3^2\)
\(=2^2.25-2^2.14\)
\(=2^2.\left(25-14\right)\)
\(=2^2.11\)
\(=4.11=44\)
a.\(\hept{\begin{cases}4^8.2^{20}=2^{16}.2^{20}=2^{36}\\9^{12}.27^5.81^4=3^{24}.3^{15}.3^{12}=3^{51}\\64^3.4^5.16^2=2^{18}.2^{10}.2^8=2^{36}\end{cases}}\)
b.\(\hept{\begin{cases}25^{20}.125^4=5^{40}.5^{12}=5^{52}\\x^7x^4x^3=x^{14}\\3^6.4^6=12^6\end{cases}}\)
c.\(\hept{\begin{cases}8^4.2^3.16^2=2^{12}.2^3.2^8=2^{23}\\2^3.2^2.8^3=2^3.2^2.2^9=2^{14}\end{cases}}\)
a/ 25x+1.1252=6254
<=> (52)x+1.(53)2=(54)4
<=> 52x+2.56 = 516
<=> 52x+2=510
=> 2x+2=10 => x=4
b/ 9x=273.35
<=> 32x=39.35=314
=> 2x=14 => x=7
c/ 16x.85=647
<=> (24)x.(23)5=(26)7
<=> 24x.215=242
<=> 24x=227
=> 4x=27 => x=27/4