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Bài 1:
a, \(\frac{1}{-16}-\frac{3}{45}=\frac{-1}{16}-\frac{1}{15}\)
\(=\frac{-15}{240}-\frac{16}{240}\)
\(=\frac{-31}{240}\)
b, \(=\frac{-10}{12}-\frac{-12}{12}\)
\(=\frac{2}{12}=\frac{1}{6}\)
c, \(=\frac{-30}{6}-\frac{1}{6}\)
\(=\frac{-31}{6}\)
Bài 2:
a, \(x=-\frac{1}{2}-\frac{3}{4}\)
\(x=-\frac{1}{4}\)
b, \(\frac{1}{2}+x=-\frac{11}{2}\)
\(x=-\frac{11}{2}-\frac{1}{2}\)
\(x=-6\)
Bạn nhớ k đúng và chọn câu trả lời này nhé!!!! Mình giải đúng và chính xác hết ^_^
A=\(\frac{10^8-1+3}{10^8-1}\)=1+\(\frac{3}{10^8-1}\)
B=\(\frac{10^8-3+3}{10^8-3}\)=1+\(\frac{3}{10^8-3}\)
Vì \(\frac{3}{10^8-1}\)<\(\frac{3}{10^8^{ }-3}\)
=>A<B
A = \(\frac{10^8+2}{10^8-1}\)
A = \(\frac{100000000+2}{100000000-1}\)
A = \(\frac{100000002}{99999999}\)
A = 1,00000003
B = \(\frac{10^8}{10^8-3}\)
B = \(\frac{100000000}{100000000-3}\)
B = \(\frac{100000000}{99999997}\)
B = 1,00000003
Vì 1,00000003 = 1,00000003
nên A = B
dug thi tk nha
1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)
a)\(19\frac{5}{8}:\frac{7}{12}-15\frac{1}{4}:\frac{7}{12}\)
=(\(19\frac{5}{8}-15\frac{1}{4}\)):\(\frac{7}{12}\)
=(\(19\frac{10}{16}-15\frac{4}{16}\)):\(\frac{7}{12}\)
=\(4\frac{6}{16}:\frac{7}{12}\)
=\(\frac{35}{8}:\frac{7}{12}\)
=\(\frac{35}{8}\cdot\frac{12}{7}\)
=\(\frac{15}{2}\)
b)2/5*1/3-2/15:1/5+3/5*1/3
=2/15-2/3+1/5
=-8/15+1/5
=-1/3
aidi qua dong tinh nho h chom minh nhe
\(a)\frac{-3}{4}+\frac{3}{7}+-\frac{1}{4}+\frac{4}{9}+\frac{4}{7}\)
\(=\left(\frac{-3}{4}+-\frac{1}{4}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{9}\)
\(=-1+1+\frac{4}{9}\)
\(=\frac{4}{9}\)
\(\frac{-3}{4}+\frac{3}{7}+\frac{-1}{4}+\frac{4}{9}+\frac{4}{7}\)
\(=\left(\frac{-3}{4}+\frac{-1}{4}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{9}\)
\(=\left(-1\right)+1+\frac{4}{9}\)
\(=0+\frac{4}{9}\)
\(=\frac{4}{9}\)
\(a)x+30\%x=-1,31\)
\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)
\(\Leftrightarrow10x+3x=-13,1\)
\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)
\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=9\)
\(\Leftrightarrow6x-3=18\)
\(\Leftrightarrow x=\frac{7}{2}\)
(1 - 1/7) x (1 - 2/7) x ............(1 - 10/7)
= 6/7 x 5/7 x ..... x -3/7
=6/7 x 5/7x 4/7 x 3/7x 2/7 x 1/7 x 0 x -1/7x -2/7 x -3/7
=0
nhớ tk cho mình nha
thanks nha