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a Ta có
1/9.3^4.3^n=3^7
=> 1/3^2.3^4.3^n=3^7
=> 3^2.3^n=3^7
=>3^2+n=3^7
=> 2+n=7
=> n=5( tick nhé)
1.
Đặt $A=2+2^2+2^3+...+2^{100}$
$2A=2^2+2^3+2^4+...+2^{101}$
$\Rightarrow 2A-A=2^{101}-2$
$\Rightarrow A=2^{101}-2$
Có:
$A+n=510$
$2^{101}-2+n=510$
$n=510+2-2^{101}=512-2^{101}$
2.
$A=7+(7^2+7^3)+(7^4+7^5)+....+(7^{20}+7^{21})$
$=7+7^2(1+7)+7^4(1+7)+...+7^{20}(1+7)$
$=7+(1+7)(7^2+7^4+....+7^{20})$
$=7+8(7^2+7^4+...+7^{20)$
$\Rightarrow A$ chia 8 dư 7.
A = 1 + 2 + 22 + 23 + 24 + ... + 2n
2A=2(1 + 2 + 22 + 23 + 24 + ... + 2n)
2A=2+22+...+2n+1
2A-A=(2+22+...+2n+1)-(1+2+22+...+2n)
A=2n+1-1
B = 7 + 71 + 72 + 73 + 74 + .... + 7n+1
7B=7( 7 + 71 + 72 + 73 + 74 + .... + 7n+1)
7B=72+72+...+7n+2
7B-B=(72+72+...+7n+2)-(7+71+...+7n+1)
6B=7n+2-7-71
B=(7n+2-14)/4
A)\(M=1+3+3^2+...+3^9\)\(\Rightarrow3M=3+3^2+3^3+...+3^{10}\)\(\Rightarrow3M-M=\left(3+3^2+3^3+...+3^{10}\right)-\left(1+3+3^2+...+3^9\right)\)
\(\Rightarrow2M=3^{10}-1\)\(\Rightarrow2M+1=3^{10}\)\(\Rightarrow n=10\)
B) \(A=1+4^2+...+4^{99}\)\(\Rightarrow4A=4+4^3+4^4+...+4^{100}\)\(\Rightarrow4A-A=\left(4+4^3+4^4+...+4^{100}\right)-\left(1+4^2+...+4^{99}\right)\)
\(\Rightarrow3A=4^{100}+4-4^2-1\Rightarrow3A=4^{100}-13\Rightarrow3A+13=4^{100}\Rightarrow n=100\)
a,1/9.34.3n=37
a,32.3n=37
=>2+n=7
n=7-2
n=5