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Bài 10:
a) (1/3)n = 1/81
=> (1/3)n = (1/3)4
=> n = 4
b) -512/343 = (-8/7)n
=> (-8/7)3 = (-8/7)n
=> 3 = n (hay n = 3)
c) (-3/4)n = 81/256
=> (-3/4)n = (-3/4)4
=> n = 4
d) 64/(-2)n = (-2)3
=> 64/(-2)n = -8
=> (-2)n = -8
=> (-2)n = (-2)3
=> n = 3
Bài 11: (không có y để tìm nhé)
a) (0,4x - 1,3)2 = 5,29
=> (0,4x - 1,3)2 = (2,3)2
=> 0,4x - 1,3 = 2,3
=> 0,4x = 3,6
=> x = 9
b) (3/5 - 2/3x)3 = -64/125
=> (3/5 - 2/3x)3 = (-4/5)3
=> 3/5 - 2/3x = -4/5
=> 2/3x = 7/5
=> x = 21/10
2.Tìm x, biết
a,(x-1)3=3 (x-1)3=343
=> (x-1)3=73
=> x -1 = 7
=> x = 8
B, (X-2)4=4096
(X-2)4= 84
=> x - 2 = 8
=> x = 10
C,(2x2-13)4=(-5)4
=> 2x2-13 = -5
=> 2x2 = 8
=> x2 = 4
=> x = 2
Study well
a. (x-1)3 = 343
=> (x-1)3 = 73
=> x - 1 = 7
=> x = 7 + 1
=> x = 8
a, x:(1/2)3=-1/2
x:1/8= -1/2
x= -1/2.1/8
x=-1/16
b,(3/4)5.x=(3/4)7
x=(3/4)7:(3/4)5
x= (3/4)2
c,(2/5)^8:x=(2/5)^6
x=.......
như cái trên nha lm giống thế
\(\frac{1}{9}.27^n=3^n\)
\(\Rightarrow\frac{3^n}{27^n}=\frac{1}{9}\)
\(\Rightarrow\left(\frac{3}{27}\right)^n=\frac{1}{9}\)
\(\Rightarrow\left(\frac{1}{9}\right)^n=\frac{1}{9}\)
\(\Rightarrow n=1\)
a) $(x-1)^3$=343
$=>(x-1)^3=7^3$
$=>x-1=7$
$=>x=8$
b) (số sai rồi nha bạn, ra lẻ lắm)
c) $(x-4)^2=(x-4)^4$
$=>(x-4)^4-(x-4)^2=0$
$=>(x-4)^2[(x-4)^2-1]=0$
\(=>\left[{}\begin{matrix}\left(x-4\right)^2=0\\\left(x-4\right)^2-1=0\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}\left(x-4\right)^2=0\\\left(x-4\right)^2=1\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}x-4=0\\x-4=1\\x-4=-1\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}x=4\\x=5\\x=3\end{matrix}\right.\)
a,\(\left(x-1\right)^3=343\)
\(\Rightarrow x-1=7\Rightarrow x=8\)
b, \(\left(x-2\right)^4=4096\)
\(\Rightarrow x-2=8\Rightarrow x=10\)
c, \(\left(x-4\right)^2=\left(x-4\right)^4\)
\(\Rightarrow\left(x-4\right)^2=\left[\left(x-4\right)^2\right]^2\)
\(\Rightarrow x-4=\left(x-4\right)^2\)
\(\Rightarrow\left(x-4\right)-\left(x-4\right)^2=0\)
\(\Rightarrow\left(x-4\right)\left(1-x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-4=0\\5-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=5\end{matrix}\right.\)
Chúc bạn học tốt!!!
1) \(2^x=4^3\)
=> 2x = (22)3
=> 2x = 26
=> x = 6
2) \(\left(\frac{1}{7}\right)^x=\left(\frac{1}{343}\right)^3\)
=> \(\left(\frac{1}{7}\right)^x=\left[\left(\frac{1}{7}\right)^3\right]^3\)
=> \(\left(\frac{1}{7}\right)^x=\left(\frac{1}{7}\right)^9\)
=> x = 9
Bài làm:
1) \(2^x=4^3\)
\(\Leftrightarrow2^x=2^6\)
\(\Rightarrow x=6\)
2) \(\left(\frac{1}{7}\right)^x=\left(\frac{1}{343}\right)^3\)
\(\Leftrightarrow\left(\frac{1}{7}\right)^x=\left(\frac{1}{7}\right)^9\)
\(\Rightarrow x=9\)