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a) 17 + 15 + (-27)
= (17 - 27) + 15
= -10 + 15
= 5
b) 13.75 + 25.13 - 300
= 13.(75 + 26) - 300
= 13.100 - 300
= 1300 - 300
= 1000
c) 80 - (4.5² - 5.2³) + 2021⁰
= 80 - (4.25 - 5.8) + 1
= 80 - (100 - 40) + 1
= 80 - 60 + 1
= 20 + 1
= 21
a) \(A=80-\left(4.5^2-3.2^3\right)\)
\(A=80-2\left(2.25-3.4\right)\)
\(A=80-76\)
\(A=4\)
b) \(B=12+\left(-25\right)\)
\(B=12-25\)
\(B=-13\)
a)17.85-15.17-120
=17.(85-17)-120
=17.68-12
=1156-120
=1036
b)100:[30-(6-1)^ 2]
=100 :[30-5^ 2]
= 100:[30-25]
=100:5=20
c)/-10/+4+3.2^3+(-14)
=10+4+3.8 +(-14)
=14+24+(-14)
=[14 +(-14)]+24
=0+24=24
d)20-[30-(5-1)^ 2: 2]
=20-[30-4^2:2]
=20-[30-8]
=20-22=-2
e)80-(4.5^2-3.2^3)
= 80-(4.25-3.8)
=80-(4.25-3.2.4)
=80-4.(25-3.2)
= 80-4.19
= 80-76=4
g)35-{12-[-14+6-2)]}
=35 -{12-14-6+2}
=35-12+14+6-2
=23+14+6-2
=37+6-2
=43-2=41
11 + (- 7) . 12 + (- 48) : (- 4) + 52
= 11 + (- 84) + 12 + 25
= - 73 + 37
= - 36
\(a)\)
\(\left(-31\right)+\left(50-19\right)-\left(150-31\right)\)
\(=\left(-31\right)+50-19-150+31\)
\(=\left(-150\right)-19\)
\(=-169\)
\(b)\)
\(25.\left(45-17\right)-45.\left(25-17\right)\)
\(=25.45-25.17-45.25+45.17\)
\(=0\)
\(c)\)
\(\frac{-1}{12}+\frac{4}{3}=\frac{5}{4}\)
\(d)\)
\(3+\frac{-5}{20}+\frac{30}{75}+\frac{-7}{4}\)
\(=\left(\frac{3}{5}+\frac{30}{75}\right)-\left(\frac{5}{20}+\frac{7}{4}\right)\)
\(=1-2\)
\(=-1\)
a) (-31)+(50-19)-(150-31)
= (-31)+50+(-19)-150+(-31)
= (-31)+50-150+(-19)-(-31)
= (-31)+(-100)+12
= -119
b) 25(45-17)-45(25-17)
= 25.45-25.17-45.25-45.17
= 25(45-45)-25(17-17)
= 0
c) -1/12 + 4/3
= -1/12 + 16/12
= 15/12
= 5/4
d) 3/5+(-5)/20+30/75+(-7)/4
= 45/75+30/75+(-5)/20+(-35)/20
= 1+(-2)
= -1
a.\(4.5^2-3.2^3+3^3:3^2=4\left(5^2-3.2\right)+3=4.19+3=79\)
b.\(28.76+24.28-28.20=28\left(76+24-20\right)=28.80=2240\)
[-12] + 83 + [-48] + 17
= 83 -12 [-48] + 17
= 71-48 +17
=23 + 17
=40