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\(-\frac{3}{5}.\frac{11}{7}+\frac{3}{-5}.\frac{4}{7}+\frac{23}{7}\)
\(=\frac{-3}{5}\left(\frac{11}{7}+\frac{4}{7}\right)+\frac{23}{7}\)
\(=\frac{-3}{5}.\frac{15}{7}+\frac{23}{7}\)
\(=\frac{-9}{7}+\frac{23}{7}=2\)
= 280 : [25 + ( 30 - 3 mũ 3 ) ]
= 280 : [ 25 + ( 30 - 27 ) ]
= 280 : ( 25 + 3 )
= 280 : 28
=10
\(a,25.\left(7-27\right)+27.25\)
\(=25.7-27+27.25\)
\(=27.\left(25+25\right)-7\)
\(=27.50-7=135-7=128\)( ko chắc )
\(b,\left(-3\right)^2.\left(-2\right)^3\)
\(=9.\left(-8\right)=-72\)
= [ 60/90 - ( 12/15 + 10/15) ] : 6/5
= ( 2/3 - 22/15 ) x 5/6
= ( 10/15 - 22/15 ) x 5/6
= -12/15 x 5/6
= -60/90
= -2/3
( 15/10 x 4/9 - ( 4/5 + 2/3 )) : 6/5
( 15/10 x 4/9 - ( 12/15 + 10/15 )) : 6/5
(30/45 - 66/45 ) : 6/5
-12/15 : 6/5 ( đã rút gọn -36/45 = -12/15 )
-2/3
k mk na <3
Q = 14.29+14.71+(1+2+3+4+...+99).(199199.198-198198.199)
= 14.(29+71) + (1+2+3+4+...+99) . (199.101.198-198.1001.199)
= 14.100 + (1+2+3+4+...+99) . 0
= 1400 + 0
= 1400
Q=14(29+71)+(1+2+3+...+99)(199.1001.198-198.1001.199)=14.100+(1+2+3+...+99).0=1400
81 : 3^2 + 5 x 3
= 81 : 9 + 5 x 3
= 9 + 5 x 3
= 9 + 15
= 24
81 : 3^2 + 5 x 3 = 3^4 : 3^2 + 5 x 3
= 3^2 + 15 = 9 + 15 = 24
\(-\frac{1}{2}+\frac{2}{3}-\frac{3}{4}+\frac{4}{5}\)
\(=\left(-\frac{1}{2}-\frac{3}{4}\right)+\left(\frac{2}{3}+\frac{4}{5}\right)\)
\(=\left(-\frac{2}{4}-\frac{3}{4}\right)+\left(\frac{10}{15}+\frac{12}{15}\right)\)
\(=\left(\frac{-2-3}{4}\right)+\left(\frac{10+12}{15}\right)\)
\(=\left(\frac{-5}{4}\right)+\left(\frac{22}{15}\right)\)
\(=\frac{-75}{60}+\frac{88}{60}\)
\(=\frac{-75+88}{60}\)
\(=\frac{13}{60}\)
Mình ghi rõ từng chi tiết rồi nha , chúc bạn học tốt !!!
-1/2+ 2/3 - 3/4 + 4/5
= (-1/2-3/4) + (2/3+4/5)
= -5/4 + 22/15
= 13/60