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a) \(\dfrac{7}{11}+\dfrac{3}{4}+\dfrac{4}{11}+\dfrac{1}{4}=\left(\dfrac{7}{11}+\dfrac{4}{11}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=1+1=2\)
b) \(\dfrac{72}{99}-\dfrac{28}{99}-\dfrac{14}{99}=\dfrac{72-28-14}{99}=\dfrac{30}{99}=\dfrac{10}{33}\)
a) 7/11+3/4+4/11+1/4
=(7/11+4/11)+(3/4+1/4)
= 1 + 1
= 2.
b) 72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99- 42/99
= 30/99=10/33.
c) 69,78+35,97+30,22
=(69,78+30,22)+35,97
= 100 +35,97
= 135,97.
d) 83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45- 73,45
= 10.
=0,8x2x48+1,6x2+1,6x50
=1,6x48+1,6x2+1,6x50
=1,6x(48+2+50)
=1,6x100
=160
Đáp án + Giải thích các bước giải:
69
,
78
×
75
%
+
69
,
78
×
1
4
+
69
,
78
×
99
=
69
,
78
×
3
4
+
69
,
78
×
1
4
+
69
,
75
×
99
=
69
,
78
×
(
3
4
+
1
4
+
99
)
=
69
,
78
×
(
1
+
99
)
=
69
,
78
×
100
=
6978
69,78 x 75 % + 69,78 x 1/4 + 69,78 x 1/4
= 69,78 x 3/4 + 69,78 x 1/4 + 69,78 x 1/4
= 69,78 x ( 3/4 + 1/4 + 1/4 )
=69,78 x 1,25 (hoặc 5/4)
= 87,225
1 Tính
7/12 - 2/7 + 1/12= (7/12-1/12)+2/7=6/12+2/7=1/2+2/7=7/14+4/14=11/14
12/17-5/17-4/17= 12-5-4/17=3/17
2a, 7/11+3/4+4/11+1/4= (7/11+4/11)+3/4+1/4=11/11+4/4=1+1=2
b)72/99-28/99-14/99= (72-28-14)/99=30/99=10/33
c)69,78+35,97+30,22= (69,78+30,22)+35,97=100+35,97=135,97
d) 83,45-30,98-42,47=83,45-(30,98+42,47)=83,45-73,45=10
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{72-28-14}{99}\)\(=\frac{30}{99}=\frac{10}{33}\)
\(\left(69,78+30,22\right)+35,97\)\(=100+35,97=135,97\)
\(83,45-\left(30,98+42,47\right)\)\(=83,45-73,45=10\)
72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99-42/99
=30/99=10/33
67,78+35,97+30,22
=(67,78+30,22)+35,97
=98+35,97
=133,97
83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
\(a,=69,78\times\left(\dfrac{3}{4}+\dfrac{1}{4}+99\right)\\ =69,78\times\left(\dfrac{4}{4}+99\right)\\ =69,78\times\left(1+99\right)=69,78\times100=6978\\ b,34,1\times8+34,1\times0,5\\ =34,1\times\left(8+0,5\right)\\ =34,1\times8,5\\ =289,85\)
a: =69,78(3/4+1/4+99)
=69,78*100
=6978
b: =34,1(8+0,5)=34,1*8,5=289,85