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a)\(\sqrt{0,09}\)+2.\(\sqrt{0,25}\)=0,3+2.0,5
=0,3+1
=1,3
b)0,5.\(\sqrt{100}\)-\(\sqrt{\frac{4}{25}}\)=0,5.10-0,4
=5-0,4
=4,6
c)(\(\sqrt{1\frac{9}{16}}\) -\(\sqrt{\frac{9}{16}}\)):5=(1,25-0,75):5
=0,5:5
=0,1
d)3.\(\sqrt{1\frac{17}{64}}\) -2.\(\sqrt{0,0625}\)=1,125-2.0,25
=1,125-0,5
=0,625
a) √0,01-√0,25=\(-\frac{2}{5}\)
b) 0,5.√100-√14
= 5 -\(\sqrt{14}\)
= 5-\(\sqrt{14}\)
\(a,\sqrt{0,01}-\sqrt{0,25}=\sqrt{\frac{1}{100}}-\sqrt{\frac{1}{4}}=\frac{1}{10}-\frac{1}{2}=\frac{1}{10}-\frac{5}{10}=-\frac{4}{10}=-\frac{2}{5}\)
\(b,0,5\sqrt{100}-\sqrt{\frac{1}{4}}=0,5\cdot10-\frac{1}{2}=\frac{5}{10}\cdot10-\frac{1}{2}=5-\frac{1}{2}=\frac{9}{2}\)
a) \(\sqrt{16x}+\frac{3}{4}=2\sqrt{\frac{4}{25}}+0,01\cdot\sqrt{100}\)
=> \(\sqrt{16}\cdot\sqrt{x}+\frac{3}{4}=2\cdot\frac{2}{5}+\frac{1}{100}\cdot10\)
=> \(4\cdot\sqrt{x}+\frac{3}{4}=\frac{4}{5}+\frac{1}{10}\cdot1\)
=> \(4\cdot\sqrt{x}+\frac{3}{4}=\frac{4}{5}+\frac{1}{10}\)
=> \(4\cdot\sqrt{x}+\frac{3}{4}=\frac{8}{10}+\frac{1}{10}=\frac{9}{10}\)
=> \(4\cdot\sqrt{x}=\frac{9}{10}-\frac{3}{4}=\frac{3}{20}\)
=> \(\sqrt{x}=\frac{3}{20}:4\)
=> \(\sqrt{x}=\frac{3}{80}\)
=> \(x=\frac{9}{6400}\)
Vậy x = 9/6400
b) \(2\frac{3}{4}x=3\frac{1}{7}:0,01\)
=> \(\frac{11}{4}x=\frac{22}{7}:\frac{1}{100}\)
=> \(\frac{11}{4}x=\frac{22}{7}\cdot100\)
=> \(\frac{11}{4}x=\frac{2200}{7}\)
=> \(x=\frac{2200}{7}:\frac{11}{4}=\frac{2200}{7}\cdot\frac{4}{11}=\frac{800}{7}\)
Vậy x = 800/7
c) \(\left|x\right|+3^2=2^2+\left(\frac{1}{2}\right)^3\)
=> \(\left|x\right|+9=4+\frac{1}{8}\)
=> \(\left|x\right|+9=\frac{33}{8}\)
=> \(\left|x\right|=\frac{33}{8}-9=-\frac{39}{8}\)
Vì \(\left|x\right|\ge0\)mà \(-\frac{39}{8}< 0\)
=> x không thỏa mãn
1.
0,2 . \(\sqrt{100}\) - \(\sqrt{\dfrac{16}{25}}\)
= 0,2 . 10 - \(\dfrac{4}{5}\)
= 2 - \(\dfrac{4}{5}\)
= \(\dfrac{6}{5}\)
1/ \(0,2.\sqrt{100}-\sqrt{\dfrac{16}{25}}\)
\(=0,2.10-0,8\)
\(=2-0,8=1,2\)
2/ \(\dfrac{2^7.9^3}{6^5.8^2}\)
\(=\dfrac{93312}{497664}=\dfrac{3}{16}=0,1875\)
3/ \(\sqrt{0,01}-\sqrt{0,25}\)
\(=0,1-0,5\)
\(=-0,4\)
4/ \(0,5.\sqrt{100}-\sqrt{\dfrac{1}{4}}\)
\(=0,5.10-0,5\)
\(=5-0,5=4,5\)
5/ \(7.\sqrt{0,01}+2.\sqrt{0,25}\)
\(=7.0,1+2.0,5\)
\(=0,7+1=1,7\)
6/ \(0,5.\sqrt{100}-\sqrt{\dfrac{1}{25}}\)
\(=0,5.10-0,2\)
\(=5-0,2=4,8\)
\(\sqrt{81}=9\)
\(\sqrt{0,64}=0,8\)
\(\sqrt{\frac{49}{100}}=\frac{7}{10}\)
\(\sqrt{8100}=90\)
\(\sqrt{100=}10\)
\(\sqrt{0,01}=0,1\)
\(\sqrt{\frac{4}{25}}=\frac{2}{5}\)
\(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}\)
\(\sqrt{81}=9\);\(\sqrt{0,64}=0,8\);\(\sqrt{\frac{49}{100}}=\frac{7}{10}\);\(\sqrt{8100}=90\); \(\sqrt{100}=10\); \(\sqrt{0,01}=0,1\); \(\sqrt{\frac{4}{25}}=\frac{2}{5}\); \(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}=\frac{3}{110}\)
\(100\times\sqrt{0,01}-0,5\times\sqrt{400}+\sqrt{0,09}=100\times0,1-0,5\times20+0,3\)
\(=10-10+0,3=0+0,3=0,3\)
0,3