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2\(^1\)=2
4\(^2\)= 16
8 = 8
10\(^3\)= 1000
3 = 3
5\(^2\)= 25
7\(^2\)= 49
9\(^2\)= 81
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học tốt
1/A=1.21.22.23.24.25 câu 2 làm tương tự
A.2=2.22.23.24.25.26
A.2-A=(2.22.23.24.25.2 mũ 6)-(1.21.22.23.24.25)
A=26-1
3 A=1+3+32+33+...37
3.A=3+32+33+34...+38
2A=38-1
A=(38-1):2
\(\frac{-8}{10}.\frac{74}{7}+\frac{17}{7}.\frac{-8}{13}+\frac{3}{5}=\frac{-8}{7}.\frac{37}{5}+\frac{-8}{7}.\frac{17}{13}+\frac{3}{5}\)
\(=\frac{-8}{7}.\left(\frac{37}{5}+\frac{17}{13}\right)+\frac{3}{5}=\frac{-8}{7}.\frac{566}{65}+\frac{3}{5}\)
\(=\frac{-4528}{455}+\frac{273}{455}=\frac{-4255}{455}=\frac{851}{91}\)
1:
a)10/20-15/20+16/20=-5/20+16/20
=11/20.
b)2/3+8/3:8/5=2/3+5/3
=7/3.
2:a)Ta có:
2x=1/4=3/4
2x=4/4=1
x=1:2
x=0,5
b)x:(2/12-1/12)=-3/8.
x:1/12=-3/8.
x=-3/8x1/12.
x=-1/32.
\(8-12x+6x^2-x^3\)
\(=\left(2-x\right)^3\)
\(125x^3-75x^2+15x-1\)
\(=\left(5x-1\right)^3\)
\(x^2-xz-9y^2+3yz\)
\(=\left(x-3y\right)\left(x+3y\right)-z\left(x-3y\right)\)
\(=\left(x-3y\right)\left(x+3y-z\right)\)
\(x^3-x^2-5x+125\)
\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)
\(=\left(x+5\right)\left(x^2-5x+25-x\right)\)
\(=\left(x+5\right)\left(x^2-6x+25\right)\)
\(x^3+2x^2-6x-27\)
\(=x^3+5x^2+9x-3x^2-15x-27\)
\(=x\left(x^2+5x+9\right)-3\left(x^2+5x+9\right)\)
\(=\left(x-3\right)\left(x^2+5x+9\right)\)
\(12x^3+4x^2-27x-9\)
\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)
\(=\left(3x+1\right)\left(4x^2-9\right)\)
\(=\left(3x+1\right)\left(2x-3\right)\left(2x+3\right)\)
\(4x^4+4x^3-x^2-x\)
\(=4x^3\left(x+1\right)-x\left(x+1\right)\)
\(=x\left(x+1\right)\left(4x^2-1\right)\)
\(=x\left(x+1\right)\left(2x-1\right)\left(2x+1\right)\)
a) = (3.23)3.3-(2.3)4.25
= 33.(23)3.3-24.34.25
= 34.29-29.34
=0
\(3^{2018}\left(3^{20}:\left(3^8\cdot3^{11}\right)+2\cdot3\right)=3^{2018}\left(3^{20}:3^{19}+2\cdot3\right)\)
\(=3^{2018}\left(3+2\cdot3\right)=3^{2018}\cdot9=3^{2018}\cdot3^2\)
\(=3^{2020}\)
(-8)2.33 = 64.27 = 1728