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LP
2
20 tháng 2 2017
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Leftrightarrow\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+329}{5}+4=0\)
\(\Leftrightarrow\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\frac{329}{5}=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Mà \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{5}\ne0\Rightarrow x+329=0\Rightarrow x=-329\)
Vậy x = - 329
20 tháng 2 2017
Ta có:
\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\)\(\left(\frac{x+349}{5}-4\right)=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
do số trong ngoặc khác 0 nên
pt <=> x+329=0
<=> x=-329
PD
2
16 tháng 3 2017
\(pt\Leftrightarrow\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\frac{x+329}{5}=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{5}\right)=0\)
Mà \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{5}\ne0\)
\(\Rightarrow x+329=0\Rightarrow x=-329\)
30 tháng 1 2020
b) \(\left|5x-3\right|-x=7\)
\(\Rightarrow\left|5x-3\right|=7+x\)
\(\Rightarrow\orbr{\begin{cases}5x-3=7+x\\5x-3=-\left(7+x\right)\end{cases}\Rightarrow\orbr{\begin{cases}5x-3=7+x\\5x-3=-7-x\end{cases}\Rightarrow}\orbr{\begin{cases}5x-x=7+3\\5x+x=-7+3\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}4x=10\\6x=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{2}\\x=-\frac{2}{3}\end{cases}}}\)
Vậy ....................
30 tháng 1 2020
Bạn ơi !!! ý A tham khảo tại link này nè :
https://h.vn/hoi-dap/question/394208.html
~ Học tốt ~
21 tháng 3 2018
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}\)\(+\frac{x+349}{5}=0\)
=> \(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)\)\(+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)\)\(+\left(\frac{x+349}{5}-4\right)=0\)
=> \(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}\)\(+\frac{x+329}{324}+\frac{x+329}{5}=0\)
=> \(\left(x+329\right)\)\(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\)\(=0\)
=> \(x+329=0\)\(\left(do\frac{1}{327}+...+\frac{1}{324}+\frac{1}{5}\ne0\right)\)
=> \(x=-329\)
Vậy x = -329
NP
9
8 tháng 1 2017
Ta co
\(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4\)=0
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Rightarrow\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}>0\)
\(\Rightarrow x+329=0\Rightarrow x=-329\)
Vay \(x=-329\)
TH
0
T
1
24 tháng 12 2016
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Leftrightarrow\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+329+20}{5}=0\)
\(\Leftrightarrow\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+329}{5}+4=0\)
\(\Leftrightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+329}{5}=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
\(\Leftrightarrow x+329=0\). Do \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\ne0\)
\(\Leftrightarrow x=-329\)
TT
2
30 tháng 6 2019
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Leftrightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left[x+329\right]\cdot\left[\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right]=0\)
\(\Leftrightarrow x+329=0\) vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}>0\)
\(\Leftrightarrow x=-329\)
Vậy x = -329
30 tháng 6 2019
Trả lời:
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
\(\Leftrightarrow x+329=0\Leftrightarrow x=-329\)
Vậy \(x=-329\)
~ Học tốt ~
\(\Leftrightarrow\frac{x-5}{325}-1+\frac{x-6}{324}-1=\frac{x-7}{323}-1+\frac{x-8}{322}-1\)
\(\Leftrightarrow\frac{x-330}{325}+\frac{x-330}{324}-\frac{x-330}{323}-\frac{x-330}{322}=0\)
\(\Leftrightarrow\left(x-330\right)\left(\frac{1}{325}+\frac{1}{324}-\frac{1}{323}-\frac{1}{322}\right)=0\)
Ma \(\frac{1}{325}+\frac{1}{324}-\frac{1}{323}-\frac{1}{322}\ne0\)
\(\Rightarrow x-330=0\)
\(\Rightarrow x=330\)
\(\frac{x-5}{325}+\frac{x-6}{324}=\frac{x-7}{323}+\frac{x-8}{322}\)
\(\Leftrightarrow\left[\frac{x-5}{325}-1\right]+\left[\frac{x-6}{324}-1\right]=\left[\frac{x-7}{323}-1\right]+\left[\frac{x-8}{322}-1\right]\)
\(\Leftrightarrow\frac{x-5-325}{325}+\frac{x-6-324}{324}=\frac{x-7-323}{323}+\frac{x-8-322}{322}\)
\(\Leftrightarrow\frac{x-330}{325}+\frac{x-330}{324}=\frac{x-330}{324}+\frac{x-330}{332}\)
\(\Leftrightarrow\frac{x-330}{325}+\frac{x-330}{324}=\frac{x-330}{324}+\frac{x-330}{332}=0\)
Auto làm nốt :v