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a,\(\frac{25}{42}-\frac{20}{63}=\frac{5}{18}\)
b,\(\frac{9}{50}-\frac{13}{75}-\frac{1}{6}\)
=\(\frac{1}{150}-\frac{1}{6}\)
=\(-\frac{4}{25}\)
c,\(\frac{2}{15}+\frac{-2}{65}-\frac{4}{39}\)
=\(\frac{32}{195}-\frac{4}{39}\)
=\(\frac{4}{65}\)
a,=75/126-40/126=35/126=5/18
b,=27/150-26/150-25/150=-4/25
c,=26/195+-6/195-20/195=0
Bài1
a) 25/42 - 20/63 =5/18
b) 9/50 - 13/75 - 1/6 = -4/25
c) 2/15 - 2/65 - 4/39 = 0
Bài2
a) x + 7/12 =17/18-1/9 b) 29/30 - (18/23 + x)=7/69
x + 7/12 = 5/6 18/23 + x =29/30 - 7/69
x =5/6 - 7/12 18/23 +x = 199/230
x = 1/4 x = 199/230 - 18/23
x= 19/230
Đè thừa một số \(\frac{25}{156}\),mk ko lại đề bài nhé
\(A=1-\frac{2+3}{2\cdot3}+.....+\frac{11+12}{11\cdot12}-\frac{12+13}{12\cdot13}\)
\(=1-\frac{1}{2}-\frac{1}{3}+\frac{1}{3}+\frac{1}{4}-...+\frac{1}{11}+\frac{1}{12}-\frac{1}{12}-\frac{1}{13}\)
\(=\frac{1}{2}-\frac{1}{13}=\frac{11}{26}\)
a/ \(\frac{15}{-50}=-\frac{3}{10}\)
\(\frac{7}{10}\)
\(\frac{24}{-20}=-\frac{12}{10}\)
\(\Rightarrow-\frac{12}{10};-\frac{3}{10};\frac{7}{10}\)
KL: ..........................................
b/ \(\frac{17}{39}=\frac{17.20}{39.20}=\frac{340}{780}\)
\(\frac{11}{65}=\frac{11.12}{65.12}=\frac{132}{780}\)
\(\frac{9}{52}=\frac{9.15}{52.15}=\frac{135}{780}\)
\(\Rightarrow\frac{132}{780};\frac{135}{780};\frac{340}{780}\)
KL:.............................................
c/ \(\frac{17}{20}=\frac{17.9}{20.9}=\frac{153}{180}\)
\(\frac{-19}{30}=-\frac{19.6}{30.6}=-\frac{114}{180}\)
\(\frac{38}{45}=\frac{38.4}{45.4}=\frac{152}{180}\)
\(\frac{-13}{18}=-\frac{13.10}{18.10}=-\frac{130}{180}\)
\(\Rightarrow-\frac{130}{180};-\frac{114}{180};\frac{152}{180};\frac{153}{180}\)
KL:..................................
1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\frac{5^{20}.3^{29}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}=\frac{3^{29}.5^{18}.\left(25-9\right)}{3^{29}.5^{18}.\left(7-5\right)}=\frac{16}{2}=8\)
CÁC BÀI CÒN LẠI TƯƠNG TỰ HẾT NHÉ E
\(\frac{25}{12}-\frac{20}{63}=\frac{445}{252}\)
\(\frac{9}{50}-\frac{13}{75}=\frac{1}{150}\)
\(\frac{2}{19}-\frac{2}{65}-\frac{4}{39}=\frac{-8}{285}\)